Bone Collector（01背包，模板题）

C - Bone Collector

Time Limit:1000MS    Memory Limit:32768KB    64bit IO Format:%I64d & %I64u

Submit Status Practice HDU 2602

Description

Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

 

Input

The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

 

Output

One integer per line representing the maximum of the total value (this number will be less than 2 ³¹).

 

Sample Input

     
     
     
     

      
      
      
      1
5 10
1 2 3 4 5
5 4 3 2 1 
     
     
     
     

 

Sample Output

   
   
   
   

    
    
    
    14 

AC代码：

    
    
    
    
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>

using namespace std;

const int MAXN = 1010;

int n, vb;
int r[MAXN], v[MAXN];
int dp[MAXN][MAXN];

int rec(int i, int j)
{
    if (dp[i][j] >= 0)
    {
        return dp[i][j];
    }

    int res;

    if (i == n)
    {
        res = 0;
    }
    else if (j < r[i])
    {
        res = rec(i + 1, j);
    }
    else
    {
        res = max (rec(i + 1, j), rec(i + 1, j - r[i]) + v[i]);
    }

    return dp[i][j] = res;
}

int main()
{
    int t;

    scanf("%d", &t);

    while (t--)
    {
        memset(r, 0, sizeof (r));
        memset(v, 0, sizeof (v));
        memset(dp, -1, sizeof (dp));

        scanf("%d%d", &n, &vb);

        for (int i=0; i<n; i++)
        {
            scanf("%d", &v[i]);
        }

        for ( int i=0; i<n; i++)
        {
            scanf("%d", &r[i]);
        }

        printf("%d\n", rec(0, vb));
    }

    return 0;
}
    
    
    
    
一次A了！