题目链接:https://leetcode.com/problems/reverse-bits/
Reverse bits of a given 32 bits unsigned integer.
For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).
Follow up:
If this function is called many times, how would you optimize it?
思路:申请一个变量result保存结果,让其每次左移一位,和n右移一位或操作,这样每次就能得到n的最低位.
代码如下:
class Solution { public: uint32_t reverseBits(uint32_t n) { uint32_t result = 0; for(int i =0; i< 32; i++) { result = result<<1; result |= (n>>i)&1; } return result; } };参考:https://leetcode.com/discuss/77219/2ms-java-solution