zoj 1453 Surround the Trees

Graham's Scan法求解凸包问题:http://www.cnblogs.com/devymex/archive/2010/08/09/1795392.html


/*
zoj_1453    计算几何-凸包
凸包第一题。计算几何方面自己几乎是一片空白,要好好加强了~
自己按照网上讲的Graham()算法写的一个模板,要多多改善才是。
*/
#include <iostream>
#include <cstdio>
#include <cmath>
#include <algorithm>
using namespace std;
struct node
{
    double x,y,tan;
};
node tree[110];

bool cmp( node a,node b )
{
    return a.tan<b.tan;
}

double count( int a,int b )
{
    return sqrt( (tree[a].y-tree[b].y)*(tree[a].y-tree[b].y)+
                (tree[a].x-tree[b].x)*(tree[a].x-tree[b].x) );
}

double Graham( node sta,int n )
{
    int s[110];
    int i,top;
    double sum;
    node a,b;
    s[0]=0; s[1]=1; s[2]=2;
    top=2;
    for( i=3;i<n;i++ )
    {
        while( 1 )
        {
            a.x=tree[ s[top] ].x-tree[ s[top-1] ].x;
            a.y=tree[ s[top] ].y-tree[ s[top-1] ].y;
            b.x=tree[i].x-tree[ s[top] ].x;
            b.y=tree[i].y-tree[ s[top] ].y;
            if( a.x*b.y-a.y*b.x<0 )
            {
                top--;
                continue;
            }
            break;
        }
        s[ ++top ]=i;
    }
    sum=0;
    for( i=1;i<=top;i++ )
        sum+=count( s[i],s[i-1] );
    sum+=count( s[0],s[top] );
    return sum;
}

int main()
{
    int n,i;
    node sta;
    double sum;
    while( scanf( "%d",&n ) && n )
    {
        sta.x=sta.y=10000000;
        for( i=0;i<n;i++ )
        {
            scanf( "%lf%lf",&tree[i].x,&tree[i].y );
            if( sta.y>tree[i].y || ( sta.y==tree[i].y && sta.x<tree[i].x ) )
                sta=tree[i]; //记录y值最小点
        }
        if( n==1 ) printf( "0.00\n" );
        else if( n==2 ) printf( "%.2lf\n",2*count(0,1) );
        else
        {
            for( i=0;i<n;i++ )
                tree[i].tan=atan2( tree[i].y-sta.y , tree[i].x-sta.x );
            sort( tree,tree+n,cmp );
            printf( "%.2lf\n",Graham( sta,n ) );
        }
    }
    return 0;
}


你可能感兴趣的:(zoj 1453 Surround the Trees)