Note: You must not hold locks that are held in interrupt context
* while calling this function. Even if the lock has nothing to do
* with the timer in question. Here's why:
*
* CPU0 CPU1
* ---- ----
* <SOFTIRQ>
* call_timer_fn();
* base->running_timer = mytimer;
* spin_lock_irq(somelock);
* <IRQ>
* spin_lock(somelock);
* del_timer_sync(mytimer);
* while (base->running_timer == mytimer);
*
* Now del_timer_sync() will never return and never release somelock.
* The interrupt on the other CPU is waiting to grab somelock but
* it has interrupted the softirq that CPU0 is waiting to finish.
*
在调用del_timer_sync这个函数时, 不能获取在中断上下文可能要占用的锁,不然会导致死锁问题。 比如CPU0上已经获取了somelock, 然后等待定时器的完成,此时CPU1进入软中断上下文时,会首先获取somelock锁,但由于该锁已经被CPU0上的跑的代码占用了,会在CPU1上一直忙等待, 因此CPU0和CPU1的代码都不会继续跑下去了。