UVa 537 - Artificial Intelligence?
题目链接：UVa 537 - Artificial Intelligence?
字符串处理，简单题。注意几个函数：
1、strncpy，如果没有把源串全部复制完，需要手动补‘\0’。还有这个函数可以通过源串的指针确定从哪开始复制，这点刚开始没有想到。
2、atof 字符串转化为浮点数，头文件，stdlib.h。
#include <iostream>
#include <cstring>
#include <stdio.h>
#include <stdlib.h>
#include <iomanip>
using namespace std;
const int MAX_N = 1024 * 2;
char line[MAX_N];
char a[2][MAX_N / 2];
int T;
double _a[2];
int cnt;
char b[2];
int solve(int i,int len)
{
int j;
if(line[i - 1] == 'U')
{
b[cnt] = 'U';
for(j = i + 1;j < len;j++)
{
if(line[j] == 'V')
break;
}
if(line[j - 1] == 'm')
{
strncpy(a[cnt],line + i + 1,j - i - 1);
a[cnt][j - i - 1] = '\0';
_a[cnt] = atof(a[cnt]);
_a[cnt] = _a[cnt] / 1000.00;
}
else if(line[j - 1] == 'k')
{
strncpy(a[cnt],line + i + 1,j - i - 1);
a[cnt][j - i - 1] = '\0';
_a[cnt] = atof(a[cnt]);
_a[cnt] = _a[cnt] * 1000.00;
}
else if(line[j - 1] == 'M')
{
strncpy(a[cnt],line + i + 1,j - i - 1);
a[cnt][j - i - 1] = '\0';
_a[cnt] = atof(a[cnt]);
_a[cnt] = _a[cnt] * 1000000.00;
}
else
{
strncpy(a[cnt],line + i + 1,j - i);
a[cnt][j - i] = '\0';
_a[cnt] = atof(a[cnt]);
}
}
else if(line[i - 1] == 'P')
{
b[cnt] = 'P';
for(j = i + 1;j < len;j++)
{
if(line[j] == 'W')
break;
}
if(line[j - 1] == 'm')
{
strncpy(a[cnt],line + i + 1,j - i - 1);
a[cnt][j - i - 1] = '\0';
_a[cnt] = atof(a[cnt]);
_a[cnt] = _a[cnt] / 1000.00;
}
else if(line[j - 1] == 'k')
{
strncpy(a[cnt],line + i + 1,j - i - 1);
a[cnt][j - i - 1] = '\0';
_a[cnt] = atof(a[cnt]);
_a[cnt] = _a[cnt] * 1000.00;
}
else if(line[j - 1] == 'M')
{
strncpy(a[cnt],line + i + 1,j - i - 1);
a[cnt][j - i - 1] = '\0';
_a[cnt] = atof(a[cnt]);
_a[cnt] = _a[cnt] * 1000000.00;
}
else
{
strncpy(a[cnt],line + i + 1,j - i);
a[cnt][j - i] = '\0';
_a[cnt] = atof(a[cnt]);
}
}
else if(line[i - 1] == 'I')
{
b[cnt] = 'I';
for(j = i + 1;j < len;j++)
{
if(line[j] == 'A')
break;
}
if(line[j - 1] == 'm')
{
strncpy(a[cnt],line + i + 1,j - i - 1);
a[cnt][j - i - 1] = '\0';
_a[cnt] = atof(a[cnt]);
_a[cnt] = _a[cnt] / 1000.00;
}
else if(line[j - 1] == 'k')
{
strncpy(a[cnt],line + i + 1,j - i - 1);
a[cnt][j - i - 1] = '\0';
_a[cnt] = atof(a[cnt]);
_a[cnt] = _a[cnt] * 1000.00;
}
else if(line[j - 1] == 'M')
{
strncpy(a[cnt],line + i + 1,j - i - 1);
a[cnt][j - i - 1] = '\0';
_a[cnt] = atof(a[cnt]);
_a[cnt] = _a[cnt] * 1000000.00;
}
else
{
strncpy(a[cnt],line + i + 1,j - i);
a[cnt][j - i] = '\0';
_a[cnt] = atof(a[cnt]);
}
}
cnt++;
return j;
}
int main()
{
cin>>T;
int num = 0;
double result;
while(T--)
{
memset(a,0,sizeof(a));
memset(b,0,sizeof(b));
cnt = 0;
getchar();
gets(line);
int len = strlen(line);
int num1,num2;
num1 = num2 = 0;
int i;
for(i = 0;i < len;i++)
{
if(line[i] == '=')
{
i = solve(i,len);
}
}
cout<<"Problem #"<<++num<<endl;
if(b[0] == 'P')
{
if(b[1] == 'U')
{
result = _a[0] / _a[1];
cout<<"I=";
cout<<fixed<<setprecision(2)<<result;
cout<<"A"<<endl;
}
else
{
result = _a[0] / _a[1];
cout<<"U=";
cout<<fixed<<setprecision(2)<<result;
cout<<"V"<<endl;
}
}
else if(b[0] == 'U')
{
if(b[1] == 'P')
{
result = _a[1] / _a[0];
cout<<"I=";
cout<<fixed<<setprecision(2)<<result;
cout<<"A"<<endl;
}
else
{
result = _a[0] * _a[1];
cout<<"P=";
cout<<fixed<<setprecision(2)<<result;
cout<<"W"<<endl;
}
}
else if(b[0] == 'I')
{
if(b[1] == 'P')
{
result = _a[1] / _a[0];
cout<<"U=";
cout<<fixed<<setprecision(2)<<result;
cout<<"V"<<endl;
}
else
{
result = _a[0] * _a[1];
cout<<"P=";
cout<<fixed<<setprecision(2)<<result;
cout<<"W"<<endl;
}
}
cout<<endl;
}
return 0;
}