codeforces 302B. Eugeny and Play List

题意:求时间num是在第几首歌,看到这么大的数据,就用二分做,做不出来,二分实在是掌握的不好,然后就用搜索做,之后有尝试了二分的方法,切记不一样的题,边界的判断是不一样的


#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
const int MAXN = 100005;

long long arr[MAXN],brr[MAXN],crr[MAXN];
int n,m;

int main(){
    scanf("%d%d",&n,&m);
    arr[0] = 0;
    for (int i = 1; i <= n; i++){
        long long a,n;
        scanf("%lld%lld",&brr[i],&crr[i]);
        arr[i] = arr[i-1] + brr[i]*crr[i];
    }
    int cur=0;
    long long num,top=0;
    for (int i = 1; i <= m; i++){
        scanf("%lld",&num);
        while (num > top){
            cur++;
            top += brr[cur] * crr[cur];
        }
        printf("%d\n",cur);
    }
    return 0;

}


#include <cstdio>
#include <cstring>
#include <iostream>
using namespace std;
const int MAXN = 200000;
long long a[MAXN];
int n,m;

int find(long long num){
    int left=0,right=n+1;
    while (right > left+1){
        int mid = (left+right)/2;
        if (a[mid]<num)
            left = mid;
        else right = mid;;
    }
    return right;
}


int main(){
    while (scanf("%d%d",&n,&m) != EOF){
        long long a,b;
        a[0] = 0;
        for (int i = 1; i <= n; i++){
            scanf("%lld%lld",&a,&b);
            a[i] = a[i-1] + a*b;
        }
        long long num;
        for(int i = 1; i <= m; i++){
            scanf("%lld",&num);
            int pos=find(num);
            printf("%d\n",pos); 
        }   
    }
    return 0;       
}


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