Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg"
, "add"
, return true.
Given "foo"
, "bar"
, return false.
Given "paper"
, "title"
, return true.
Note:
You may assume both s and t have the same length.
class Solution { public: bool isIsomorphic(string s, string t) { if(s.length()!=t.length()) return false; int length=s.length(); map<char,char> check; map<char,bool> tcheck; for(int i=0;i<length;++i){ if(check.find(s[i])==check.end()&&tcheck[t[i]]==false){ //只能建立一对一的映射关系 check[s[i]]=t[i]; tcheck[t[i]]=true; } } for(int i=0;i<length;++i) s[i]=check[s[i]]; return s==t; } };