leetcode-Minimum Size Subarray Sum

Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn't one, return 0 instead.

For example, given the array [2,3,1,2,4,3] and s = 7,
the subarray [4,3] has the minimal length under the problem constraint.

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More practice:

If you have figured out the O(n) solution, try coding another solution of which the time complexity is O(n log n).

class Solution {
public:
    int minSubArrayLen(int s, vector<int>& nums) {
        if(s<=0||nums.empty())
            return 0;
        int begin=0,end=0;
        int size=nums.size();
        int sum=0;
        int minLen=INT_MAX;
        while(end<size){
            sum+=nums[end];
            while(sum>=s){
                if(end-begin+1<minLen)
                    minLen=end-begin+1;
                sum-=nums[begin];
                ++begin;
            }
            ++end;    
        }
        return minLen==INT_MAX?0:minLen;
    }
};


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