LeetCode - Compare Version Numbers

Compare two version numbers version1 and version1.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

Solution:

public int compareVersion(String version1, String version2) {
    String[] v1 = version1.split("\\.");
    String[] v2 = version2.split("\\.");
    int maxLength = Math.max(v1.length, v2.length);
    for(int i=0; i<maxLength; i++) {
        Integer a = i<v1.length ? Integer.parseInt(v1[i]) : 0;
        Integer b = i<v2.length ? Integer.parseInt(v2[i]) : 0;
        int res = a.compareTo(b);
        if(res != 0) return res;
    }
    return 0;
}

注意各种edge case，比如：0.0.1, 0.1 和 1.0, 1