方法一:循环元素删除 List order not maintained
// 删除ArrayList中重复元素 public static void removeDuplicate(List list) { for ( int i = 0 ; i < list.size() - 1 ; i ++ ) { for ( int j = list.size() - 1 ; j > i; j -- ) { if (list.get(j).equals(list.get(i))) { list.remove(j); } } } System.out.println(list); }
方法二:通过HashSet剔除 List order not maintained
// 删除ArrayList中重复元素 public static void removeDuplicate(List list) { HashSet h = new HashSet(list); list.clear(); list.addAll(h); System.out.println(list); }
方法三: 删除ArrayList中重复元素,List order maintained
// 删除ArrayList中重复元素,保持顺序 public static void removeDuplicateWithOrder(List list) { Set set = new HashSet(); List newList = new ArrayList(); for (Iterator iter = list.iterator(); iter.hasNext();) { Object element = iter.next(); if (set.add(element)) newList.add(element); } list.clear(); list.addAll(newList); System.out.println( " remove duplicate " + list); }