driver register到bus时候,是如何attach到匹配的device???

1.要回答这个问题,首先需要了解的是,device从哪来的?

在device add的流程中,是 device node ->platform deivice -> device。

其中这三者的实体中,都有相互包含 相互指向的。在编写dts的时候,具体的device node会包含capatiable的相关信息。在内核unflatten之后,内核的device node 代表了原来文件的具体的node。

在device结构体种内嵌了一个指针变量指向自己的device node

2.如何匹配的问题?就变成driver 定义那of_match_table中的compatible如何匹配的问题。

3.在platform_driver 注册的流程中:

/**
 * driver_attach - try to bind driver to devices.
 * @drv: driver.
 *
 * Walk the list of devices that the bus has on it and try to
 * match the driver with each one.  If driver_probe_device()
 * returns 0 and the @dev->driver is set, we've found a
 * compatible pair.
 */
int driver_attach(struct device_driver *drv)
{
	return bus_for_each_dev(drv->bus, NULL, drv, __driver_attach); //-------------------------------------a
}

static int __driver_attach(struct device *dev, void *data)
{
	struct device_driver *drv = data;

	/*
	 * Lock device and try to bind to it. We drop the error
	 * here and always return 0, because we need to keep trying
	 * to bind to devices and some drivers will return an error
	 * simply if it didn't support the device.
	 *
	 * driver_probe_device() will spit a warning if there
	 * is an error.
	 */

	if (!driver_match_device(drv, dev)) //------------------------------------------------------------------b

		return 0;

	if (dev->parent)	/* Needed for USB */
		device_lock(dev->parent);
	device_lock(dev);
	if (!dev->driver)
		driver_probe_device(drv, dev);
	device_unlock(dev);
	if (dev->parent)
		device_unlock(dev->parent);

	return 0;
}


static inline int driver_match_device(struct device_driver *drv,
				      struct device *dev)
{
	return drv->bus->match ? drv->bus->match(dev, drv) : //-----------------------------------------------------c
}

a-->b->c的流程可以看出,关键是看bus->match


4.话说回来,其实在platform bus 下的match,在每个driver reg的过程中都是一样的。具体如下:

/**
 * __platform_driver_register - register a driver for platform-level devices
 * @drv: platform driver structure
 * @owner: owning module/driver
 */
int __platform_driver_register(struct platform_driver *drv,
				struct module *owner)
{
	drv->driver.owner = owner;
	drv->driver.bus = &platform_bus_type; //-------------------------------------------------d
	if (drv->probe)
		drv->driver.probe = platform_drv_probe;
	if (drv->remove)
		drv->driver.remove = platform_drv_remove;
	if (drv->shutdown)
		drv->driver.shutdown = platform_drv_shutdown;

	return driver_register(&drv->driver);
}

d中的赋值就是对driver下的bus进行赋值的结果。那么具体的match是怎样的流程呢?

/**
 * platform_match - bind platform device to platform driver.
 * @dev: device.
 * @drv: driver.
 *
 * Platform device IDs are assumed to be encoded like this:
 * "<name><instance>", where <name> is a short description of the type of
 * device, like "pci" or "floppy", and <instance> is the enumerated
 * instance of the device, like '0' or '42'.  Driver IDs are simply
 * "<name>".  So, extract the <name> from the platform_device structure,
 * and compare it against the name of the driver. Return whether they match
 * or not.
 */
static int platform_match(struct device *dev, struct device_driver *drv)
{
	struct platform_device *pdev = to_platform_device(dev);
	struct platform_driver *pdrv = to_platform_driver(drv);

	/* When driver_override is set, only bind to the matching driver */
	if (pdev->driver_override)
		return !strcmp(pdev->driver_override, drv->name);

	/* Attempt an OF style match first */
	if (of_driver_match_device(dev, drv)) //----------------------------------------------------------------e
		return 1;

	/* Then try ACPI style match */
	if (acpi_driver_match_device(dev, drv))
		return 1;

	/* Then try to match against the id table */
	if (pdrv->id_table)
		return platform_match_id(pdrv->id_table, pdev) != NULL;

	/* fall-back to driver name match */
	return (strcmp(pdev->name, drv->name) == 0);
}
/**
 * of_driver_match_device - Tell if a driver's of_match_table matches a device.
 * @drv: the device_driver structure to test
 * @dev: the device structure to match against
 */
static inline int of_driver_match_device(struct device *dev,
					 const struct device_driver *drv)
{
	return of_match_device(drv->of_match_table, dev) != NULL;-----------------------------------------f
}

/**
 * of_match_device - Tell if a struct device matches an of_device_id list
 * @ids: array of of device match structures to search in
 * @dev: the of device structure to match against
 *
 * Used by a driver to check whether an platform_device present in the
 * system is in its list of supported devices.
 */
const struct of_device_id *of_match_device(const struct of_device_id *matches,
					   const struct device *dev)
{
	if ((!matches) || (!dev->of_node))
		return NULL;
	return of_match_node(matches, dev->of_node);-----------------------------------------g
}
/**
 * of_match_node - Tell if an device_node has a matching of_match structure
 *	@matches:	array of of device match structures to search in
 *	@node:		the of device structure to match against
 *
 *	Low level utility function used by device matching.
 */
const struct of_device_id *of_match_node(const struct of_device_id *matches,
					 const struct device_node *node)
{
	const struct of_device_id *match;
	unsigned long flags;

	raw_spin_lock_irqsave(&devtree_lock, flags);-----------------(1)
	match = __of_match_node(matches, node);-----------------------------------------------h
	raw_spin_unlock_irqrestore(&devtree_lock, flags);------------(2)
	return match;
}
static
const struct of_device_id *__of_match_node(const struct of_device_id *matches,
					   const struct device_node *node)
{
	const struct of_device_id *best_match = NULL;
	int score, best_score = 0;

	if (!matches)
		return NULL;

	for (; matches->name[0] || matches->type[0] || matches->compatible[0]; matches++) {
		score = __of_device_is_compatible(node, matches->compatible,
						  matches->type, matches->name); -------------------i
		if (score > best_score) {
			best_match = matches;
			best_score = score;
		}
	}

	return best_match;
}
e - f -g-h-i的流程就是匹配的流程,其最终就是比较的device node的 capatible中的string是否与driver定义的一样

NOTE:只要对device node操作,都需要加锁。因为device node在内核有一个全局变量的head 和mutex







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