HashMap 、TreeMap、Hashtable、LinkedHashMap

HashMap 、TreeMap、Hashtable、LinkedHashMap_第1张图片

HashMap

通过一个哈希表实现,无序

class Dog {
    String color;

    Dog(String c) {
        color = c;
    }
    public String toString(){   
        return color + " dog";
    }
}

public class TestHashMap {
    public static void main(String[] args) {
        HashMap<Dog, Integer> hashMap = new HashMap<Dog, Integer>();
        Dog d1 = new Dog("red");
        Dog d2 = new Dog("black");
        Dog d3 = new Dog("white");
        Dog d4 = new Dog("white");

        hashMap.put(d1, 10);
        hashMap.put(d2, 15);
        hashMap.put(d3, 5);
        hashMap.put(d4, 20);

        //print size
        System.out.println(hashMap.size());

        //loop HashMap
        for (Entry<Dog, Integer> entry : hashMap.entrySet()) {
            System.out.println(entry.getKey().toString() + " - " + entry.getValue());
        }
    }
}

输出:

4
white dog - 5
black dog - 15
red dog - 10
white dog - 20

white dog被添加了2次,因为默认HashMap对象无法区分这两次的区别,需要添加实现hashCodeequals方法

class Dog {
    String color;

    Dog(String c) {
        color = c;
    }

    public boolean equals(Object o) {
        return ((Dog) o).color.equals(this.color);
    }

    public int hashCode() {
        return color.length();
    }

    public String toString(){   
        return color + " dog";
    }
}

TreeMap

基于红黑树实现、根据Key排序的有序表
如果直接使用

class Dog {
    String color;

    Dog(String c) {
        color = c;
    }
    public boolean equals(Object o) {
        return ((Dog) o).color.equals(this.color);
    }

    public int hashCode() {
        return color.length();
    }
    public String toString(){   
        return color + " dog";
    }
}

public class TestTreeMap {
    public static void main(String[] args) {
        Dog d1 = new Dog("red");
        Dog d2 = new Dog("black");
        Dog d3 = new Dog("white");
        Dog d4 = new Dog("white");

        TreeMap<Dog, Integer> treeMap = new TreeMap<Dog, Integer>();
        treeMap.put(d1, 10);
        treeMap.put(d2, 15);
        treeMap.put(d3, 5);
        treeMap.put(d4, 20);

        for (Entry<Dog, Integer> entry : treeMap.entrySet()) {
            System.out.println(entry.getKey() + " - " + entry.getValue());
        }
    }
}

将会抛出异常
Exception in thread "main" java.lang.ClassCastException: collection.Dog cannot be cast to java.lang.Comparable
at java.util.TreeMap.put(Unknown Source)

需要对象实现Comparable接口

class Dog implements Comparable<Dog>{
    String color;
    int size;

    Dog(String c, int s) {
        color = c;
        size = s;
    }

    public String toString(){   
        return color + " dog";
    }

    @Override
    public int compareTo(Dog o) {
        return  o.size - this.size;
    }
}

或者使用new TreeMap(comparator)构造器

    TreeMap<Dog, Integer> treeMap = new TreeMap<Dog, Integer>(
                new Comparator<Dog>() {

                    @Override
                    public int compare(Dog o1, Dog o2) {
                        return o2.size - o1.size;
                    }
                });

Hashtable

线程同步的HashMap

LinkedHashMap

LinkedHashMap是HashMap的一个子类,它保留了HashMap的所有特点同时他也记录下了元素的插入顺序,如:

class Dog {
    String color;

    Dog(String c) {
        color = c;
    }

    public boolean equals(Object o) {
        return ((Dog) o).color.equals(this.color);
    }

    public int hashCode() {
        return color.length();
    }

    public String toString(){   
        return color + " dog";
    }
}

public class TestHashMap {
    public static void main(String[] args) {

        Dog d1 = new Dog("red");
        Dog d2 = new Dog("black");
        Dog d3 = new Dog("white");
        Dog d4 = new Dog("white");

        LinkedHashMap<Dog, Integer> linkedHashMap = new LinkedHashMap<Dog, Integer>();
        linkedHashMap.put(d1, 10);
        linkedHashMap.put(d2, 15);
        linkedHashMap.put(d3, 5);
        linkedHashMap.put(d4, 20);

        for (Entry<Dog, Integer> entry : linkedHashMap.entrySet()) {
            System.out.println(entry.getKey() + " - " + entry.getValue());
        }       
    }
}

输出

red dog - 10
black dog - 15
white dog - 20

和插入顺序一致

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