利用日期、经纬度求日出日落时间 C语言程序代码（zz）
先贴在这了，后面应该用得着
http://zhidao.baidu.com/link?url=iw-hcd_tLpRtf4r2Kh-NmDPaQ10UdlunBQUWaz14J-eNEq5fw-y83ydgOTn7KX9Z_t5rGywtlFGaygRJeEYBPa
#define PI 3.1415926 #include<math.h> #include<iostream> using namespace std; int days_of_month_1[]={31,28,31,30,31,30,31,31,30,31,30,31}; int days_of_month_2[]={31,29,31,30,31,30,31,31,30,31,30,31}; long double h=-0.833; //定义全局变量 void input_date(int c[]){ int i; cout<<"Enter the date (form: 2009 03 10):"<<endl; for(i=0;i<3;i++){ cin>>c[i]; } } //输入日期 void input_glat(int c[]){ int i; cout<<"Enter the degree of latitude(range: 0°- 60°,form: 40 40 40 (means 40°40′40″)):"<<endl; for(i=0;i<3;i++){ cin>>c[i]; } } //输入纬度 void input_glong(int c[]){ int i; cout<<"Enter the degree of longitude(west is negativ,form: 40 40 40 (means 40°40′40″)):"<<endl; for(i=0;i<3;i++){ cin>>c[i]; } } //输入经度 int leap_year(int year){ if(((year%400==0) || (year%100!=0) && (year%4==0))) return 1; else return 0; } //判断是否为闰年:若为闰年，返回1；若非闰年，返回0 int days(int year, int month, int date){ int i,a=0; for(i=2000;i<year;i++){ if(leap_year(i)) a=a+366; else a=a+365; } if(leap_year(year)){ for(i=0;i<month-1;i++){ a=a+days_of_month_2[i]; } } else { for(i=0;i<month-1;i++){ a=a+days_of_month_1[i]; } } a=a+date; return a; } //求从格林威治时间公元2000年1月1日到计算日天数days long double t_century(int days, long double UTo){ return ((long double)days+UTo/360)/36525; } //求格林威治时间公元2000年1月1日到计算日的世纪数t long double L_sun(long double t_century){ return (280.460+36000.770*t_century); } //求太阳的平黄径 long double G_sun(long double t_century){ return (357.528+35999.050*t_century); } //求太阳的平近点角 long double ecliptic_longitude(long double L_sun,long double G_sun){ return (L_sun+1.915*sin(G_sun*PI/180)+0.02*sin(2*G_sun*PI/180)); } //求黄道经度 long double earth_tilt(long double t_century){ return (23.4393-0.0130*t_century); } //求地球倾角 long double sun_deviation(long double earth_tilt, long double ecliptic_longitude){ return (180/PI*asin(sin(PI/180*earth_tilt)*sin(PI/180*ecliptic_longitude))); } //求太阳偏差 long double GHA(long double UTo, long double G_sun, long double ecliptic_longitude){ return (UTo-180-1.915*sin(G_sun*PI/180)-0.02*sin(2*G_sun*PI/180)+2.466*sin(2*ecliptic_longitude*PI/180)-0.053*sin(4*ecliptic_longitude*PI/180)); } //求格林威治时间的太阳时间角GHA long double e(long double h, long double glat, long double sun_deviation){ return 180/PI*acos((sin(h*PI/180)-sin(glat*PI/180)*sin(sun_deviation*PI/180))/(cos(glat*PI/180)*cos(sun_deviation*PI/180))); } //求修正值e long double UT_rise(long double UTo, long double GHA, long double glong, long double e){ return (UTo-(GHA+glong+e)); } //求日出时间 long double UT_set(long double UTo, long double GHA, long double glong, long double e){ return (UTo-(GHA+glong-e)); } //求日落时间 long double result_rise(long double UT, long double UTo, long double glong, long double glat, int year, int month, int date){ long double d; if(UT>=UTo) d=UT-UTo; else d=UTo-UT; if(d>=0.1) { UTo=UT; UT=UT_rise(UTo,GHA(UTo,G_sun(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))),glong,e(h,glat,sun_deviation(earth_tilt(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))))); result_rise(UT,UTo,glong,glat,year,month,date); } return UT; } //判断并返回结果（日出） long double result_set(long double UT, long double UTo, long double glong, long double glat, int year, int month, int date){ long double d; if(UT>=UTo) d=UT-UTo; else d=UTo-UT; if(d>=0.1){ UTo=UT; UT=UT_set(UTo,GHA(UTo,G_sun(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))),glong,e(h,glat,sun_deviation(earth_tilt(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))))); result_set(UT,UTo,glong,glat,year,month,date); } return UT; } //判断并返回结果（日落） int Zone(long double glong){ if(glong>=0) return (int)((int)(glong/15.0)+1); else return (int)((int)(glong/15.0)-1); } //求时区 void output(long double rise, long double set, long double glong){ if((int)(60*(rise/15+Zone(glong)-(int)(rise/15+Zone(glong))))<10) cout<<"The time at which the sun rises is "<<(int)(rise/15+Zone(glong))<<":0"<<(int)(60*(rise/15+Zone(glong)-(int)(rise/15+Zone(glong))))<<" .\n"; else cout<<"The time at which the sun rises is "<<(int)(rise/15+Zone(glong))<<":"<<(int)(60*(rise/15+Zone(glong)-(int)(rise/15+Zone(glong))))<<" .\n"; if((int)(60*(set/15+Zone(glong)-(int)(set/15+Zone(glong))))<10) cout<<"The time at which the sun sets is "<<(int)(set/15+Zone(glong))<<": "<<(int)(60*(set/15+Zone(glong)-(int)(set/15+Zone(glong))))<<" .\n"; else cout<<"The time at which the sun sets is "<<(int)(set/15+Zone(glong))<<":"<<(int)(60*(set/15+Zone(glong)-(int)(set/15+Zone(glong))))<<" .\n"; } //打印结果 int main(){ long double UTo=180.0; int year,month,date; long double glat,glong; int c[3]; input_date(c); year=c[0]; month=c[1]; date=c[2]; input_glat(c); glat=c[0]+c[1]/60+c[2]/3600; input_glong(c); glong=c[0]+c[1]/60+c[2]/3600; long double rise,set; rise=result_rise(UT_rise(UTo,GHA(UTo,G_sun(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))),glong,e(h,glat,sun_deviation(earth_tilt(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))))),UTo,glong,glat,year,month,date); set=result_set(UT_set(UTo,GHA(UTo,G_sun(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))),glong,e(h,glat,sun_deviation(earth_tilt(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))))),UTo,glong,glat,year,month,date); output(rise,set,glong); system("pause"); return 0; }
来自为知笔记(Wiz)