Write a function that takes a string as input and reverse only the vowels of a string.
Example 1:
Given s = "hello", return "holle".
Example 2:
Given s = "leetcode", return "leotcede".
分析:DONE
典型的双指针问题:从前从后分别寻找(利用set加快查找速度)元音的位置,然后交换,注意边界条件即可!
class Solution { public: void swapchar(string &str,int pos1,int pos2) { char tmpch=str[pos2]; str[pos2]=str[pos1]; str[pos1]=tmpch; } string reverseVowels(string s) { char base[10]={'a','e','i','o','u','A','E','I','O','U'}; set<char> seting(base,base+10); int startpos=0,endpos=s.size()-1; while(startpos < endpos ) { while( startpos < endpos && seting.find(s[startpos]) == seting.end())//从左往右、新的、未被交换过的元音位置 startpos++; while( startpos < endpos && seting.find(s[endpos]) == seting.end()) endpos--; if(startpos < endpos) swapchar(s,startpos++,endpos--); } return s; } };
344 Reverse String
Write a function that takes a string as input and returns the string reversed.
Example:
Given s = "hello", return "olleh".
分析:DONE
字符串反转!恐怕此题会成为leetcode历史上最简单的题目!
时间复杂度o(n)
class Solution { public: void swapchar(string &str,int pos1,int pos2) { char tmpch=str[pos2]; str[pos2]=str[pos1]; str[pos1]=tmpch; } string reverseString(string s) { int halfsize=s.size()/2; for(int i=0;i < halfsize;i++) swapchar(s,i,s.size()-i-1); return s; } };
或者:
class Solution { public: string reverseString(string s) { reverse(s.begin(), s.end()); return s; } };
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原文地址:http://blog.csdn.net/ebowtang/article/details/51228095
原作者博客:http://blog.csdn.net/ebowtang
本博客LeetCode题解索引:http://blog.csdn.net/ebowtang/article/details/50668895