83. Remove Duplicates from Sorted List(Linked List-Easy)

Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.

C代码:

/** * Definition for singly-linked list. * struct ListNode { * int val; * struct ListNode *next; * }; */
struct ListNode* deleteDuplicates(struct ListNode* head) {
    struct ListNode* cur = (int *)malloc(sizeof(struct ListNode));
    cur = head;
    while(cur != NULL){
        while(cur->next != NULL && cur->val == cur->next->val){
            cur->next = cur->next->next;
        }
        cur = cur->next;
    }
    return head;
}

C++代码:

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    ListNode* deleteDuplicates(ListNode* head) {
        ListNode* cur = head;
        while(cur != NULL){
            while(cur->next != NULL && cur->val == cur->next->val){
                cur->next = cur->next->next;
            }
            cur = cur->next;
        }
        return head;
    }
};

你可能感兴趣的:(LeetCode,链表,83)