二、The specified child already has a parent. You must call removeView() on the child's parent first.

我写了一个应用程序，需要竖屏和横屏显示不同的布局

if (this.getResources().getConfiguration().orientation == Configuration.ORIENTATION_LANDSCAPE) { setNormalHorizontalView(); } else if (this.getResources().getConfiguration().orientation == Configuration.ORIENTATION_PORTRAIT) { setNormalVerticalView(); }在竖屏时会使用ActivityManager进行视图切换

mFrameLayout.removeAllViews(); switch(mPresentActivity){ case 0: mFrameLayout.addView((mLocalActivityManager.startActivity("", new Intent(GinwaveIMusic.this,GinwavePlayer.class)).getDecorView())); break; case 1: mFrameLayout.addView((mLocalActivityManager.startActivity("", new Intent(GinwaveIMusic.this,Album.class)).getDecorView())); break; case 2: mFrameLayout.addView((mLocalActivityManager.startActivity("", new Intent(GinwaveIMusic.this,GinwaveMusic.class)).getDecorView())); break; case 3: mFrameLayout.addView((mLocalActivityManager.startActivity("", new Intent(GinwaveIMusic.this,PlayList.class)).getDecorView())); break; }从竖屏切换到横屏然后再切换到竖屏时会出现The specified child already has a parent. You must call removeView() on the child's parent first.的bug，我按照提示已经添加了mFameLayout.removeAllViews()函数，但还是会出现这个问题，我想可能是由于在竖屏时已经执行过mLocalActivityManager.startActivity("", new Intent(GinwaveIMusic.this,GinwavePlayer.class)).getDecorView()方法，从横屏转换到竖屏后又会执行这个方法，而第一次切换后并没有进行对这个View进行释放，所以我在由竖屏切换到横屏时对这个View进行释放，我在onConfiguration中增加了以下代码后就没有问题了

if (this.getResources().getConfiguration().orientation == Configuration.ORIENTATION_LANDSCAPE) { if(mFrameLayout != null){ mFrameLayout.removeAllViews(); } setNormalHorizontalView(); }