多校训练赛-K Time Zone（时间模拟）

 

【题述】唯二做出来的题，虽然代码行数比题解的多了一倍...但是我的代码相对来讲，更容易理解一些

具体的解释放在代码里面很清楚了。

【题解代码】  #include #include #include #include #include int main() {   std::ios::sync_with_stdio(false);   int T;   std::cin >> T;   for (int cas = 1; cas <= T; ++cas) {     int sgn;     int a, b, x, y(0);     std::string s;     std::cin >> a >> b >> s;     sgn = (s[3] == '+' ? 1 : -1);     s = s.substr(4);     if (s.size() > 2) {       y = s.back() - '0';       s.pop_back();       s.pop_back();     }     x = std::stoi(s);     int m = (a + 24) * 60 + b;     int c = 80;     int d = sgn * (x * 10 + y);     int e = d - c;     int f = e * 6;     int g = (m + f) % 1440;     printf("%02d:%02d\n", g / 60, g % 60);   }   return 0; }

【我的代码（通过代码）】 #include #include #include int main(){     int a,b,t,hour,min,stanh;     char c[5];     while(scanf("%d",&t)!=EOF){         while(t--){             scanf("%d %d UTC%s",&a,&b,c);             int len=strlen(c);             stanh=a-8;//把输入的时间转化为 utc+0 的时间:   a-8 : b             //这里开始根据UTC后面的长度来进行判断。             //+/- X的情况（x是1位数）             if(len==2){                 if(c[0]=='+'){                     hour=stanh+c[1]-'0';                     min=b;                 }                 else{                     hour=stanh-(c[1]-'0');                     min=b;                 }             }             //+/- X的情况（x>9,x是两位数）             else if(len==3){                 if(c[0]=='+'){                     hour=stanh+(c[1]-'0')*10+(c[2]-'0');                     min=b;                 }                 else{                     hour=stanh-(c[1]-'0')*10-(c[2]-'0');                     min=b;                 }             }             // +/- X.Y的情况（x是2位数）             else if(len==4){                 if(c[0]=='+'){                     hour=stanh+c[1]-'0';                     min=b+(c[3]-'0')*6;                 }                 else{                     hour=stanh-(c[1]-'0');                     min=b-(c[3]-'0')*6;                 }             }             // +/- X.Y的情况（x是3位数）             else if(len==5){                 if(c[0]=='+'){                     hour=stanh+(c[1]-'0')*10+(c[2]-'0');                     min=b+(c[4]-'0')*6;                 }                 else{                     hour=stanh-(c[1]-'0')*10-(c[2]-'0');                     min=b-(c[4]-'0')*6;                 }             }             //处理需要进位或减位的情况             if(min<0){                 min+=60;                 hour-=1;             }             else if(min>59){                 min-=60;                 hour+=1;             }             if(hour<0){                 hour+=24;             }             else if(hour>=24){                 hour-=24;             }             printf("%02d:%02d\n",hour,min);                     }     }     return 0; }

Chiaki often participates in international competitive programming contests. The time zone becomes a big problem. 
Given a time in Beijing time (UTC +8), Chiaki would like to know the time in another time zone ss.