Python字典排序

def reverse_rank(id, score):
    values = list()
    for i, v in zip(id, score):
        values.append((i, (np.argmax(v), v[1])))
    values = sorted(values, key=lambda item: (item[1][0], item[1][1]), reverse=True)
    return values

id = ['1', '2', '3', '4']

score = [(1,0.45), (0,0.32), (1,0.53), (0,0.53)]

ranked_res = reverse_rank(id, score)