easygui系列之-打开文件显示内容

需求：提供一个文件夹浏览框，用户打开某个文件后，显示文件的内容。

代码如下：

# -*- coding: utf-8 -*-

import easygui as g
import os

file_path=g.fileopenbox(default="*.txt")

with open(file_path) as f:
    msg="文件【%s】的内容如下：" %os.path.basename(file_path)
    title="显示文件内容"
    text=f.read()
    g.textbox(msg,title,text)

继续增强功能，当用户点击“Ok”按钮的时候，比较当前文件是否修改过，如果修改过，则提示“覆盖保存”、“放弃保存”或“另存为…”，并实现相应的功能。

# -*- coding: utf-8 -*-

import easygui as g
import os

file_path = g.fileopenbox(default="*.txt")

with open(file_path) as old_file:
    title = os.path.basename(file_path)
    msg = "文件【%s】的内容如下：" % title
    text = old_file.read()
    text_after = g.textbox(msg, title, text)

if text != text_after[:-1]:
    # textbox 的返回值会追加一个换行符
    choice = g.buttonbox("检测到文件内容发生改变，请选择以下操作：", "警告", ("覆盖保存", "放弃保存", "另存为..."))
    if choice == "覆盖保存":
        with open(file_path, "w") as old_file:
            old_file.write(text_after[:-1])
    if choice == "放弃保存":
        pass
    if choice == "另存为...":
        another_path = g.filesavebox(default=".txt")
        if os.path.splitext(another_path)[1] != '.txt':
            another_path += '.txt'
        with open(another_path, "w") as new_file:
            new_file.write(text_after[:-1])

参考：
http://bbs.fishc.com/forum.php?mod=viewthread&tid=48359&extra=page%3D2%26filter%3Dtypeid%26typeid%3D398