HDU-4287-Intelligent IME

HDU-4287-Intelligent IME

http://acm.hdu.edu.cn/showproblem.php?pid=4287

开始用字典树+深搜，超时。。。。后来发现题目最多6位数，可将字符串转化成对应的数字，然后hash即可

TLE的代码

#include  
#include  
#include  
#include  
using namespace std;  
int n,m,ans;
char map[5005][8];
char word[8];
char phone[8][4]={{0,1,2},{3,4,5},{6,7,8},{9,10,11},{12,13,14},{15,16,17,18},{19,20,21},{22,23,24,25}}; 
int  num[8]={3,3,3,3,3,4,3,4};
struct node  
{  
    int count;  
    node *childs[26];  
    node()  
    {  
        count=0;  
        for(int i=0;i<26;i++)  
        childs[i]=NULL;  
    }  
};  
node *root;  
node *current,*newnode; 
void insert(char *str) //插入字符串  
{  
    int i,m;  
    current=root;  
    for(i=0;ichilds[m]!=NULL)  
        current=current->childs[m];  
        else  
        {  
            newnode=new node;  
            current->childs[m]=newnode;  
            current=newnode;  
        }  
    }  
	current->count=1;
}
int search(char *str)   //在字典树中查找一个单词是否存在  
{  
    int i,m;  
    current=root;  
    for(i=0;ichilds[m]==NULL)  
        return 0;  
        current=current->childs[m];  
    }  
    return current->count;  
}  
void del(node *head)    
{  
    int i;  
    for(i=0;i<26;i++)  
    if(head->childs[i]!=NULL)  
    del(head->childs[i]);  
    delete(head);  
}
void dfs(char str[10],int len,int t)
{
	int i,s;
	if(t==len)
	{
	    word[len]='\0';
		if(search(word))
		ans++;
	}
	s=num[str[t]-'2'];
	for(i=0;i

AC的代码

#include
#include
#include
int hashh[1000005];
int a[5005];
char str[10];
int judge(char c)
{
	if('a'<=c&&c<='c')
	return 2;
	else if('d'<=c&&c<='f')
	return 3;
	else if('g'<=c&&c<='i')
	return 4;
	else if('j'<=c&&c<='l')
	return 5;
	else if('m'<=c&&c<='o')
	return 6;
	else if('p'<=c&&c<='s')
	return 7;
	else if('t'<=c&&c<='v')
	return 8;
	else if('w'<=c&&c<='z')
	return 9;
}
int main()
{
	int t;
	int i,j,n,m,len,sum;
	scanf("%d",&t);
	while(t--)
	{
		scanf("%d%d",&n,&m);
		for(i=0;i