解决ztree搜索中多级菜单展示不全问题

ztree 官网的中的 Search Nodes 例子中，所有菜单都是连着的，如果出现某个菜单下无子节点，那么在搜索时，此节点便不会自动展开，这里给出对应的增强版代码

var setting = {
    data: {
      key: {
        title: "t"
      },
      simpleData: {
        enable: true
      }
    },
    view: {
      fontCss: getFontCss
    }
  };
  var zNodes =[
    { id:1, pId:0, name:"系统参数",open:true},
    { id:11, pId:1, name:"通用参数"},
    { id:111, pId:11, name:"状态A"},
    { id:112, pId:11, name:"状态B"},
    { id:12, pId:1, name:"日志"},
    { id:121, pId:12, name:"操作类型"},
    { id:122, pId:12, name:"操作结果"},
    { id:1221, pId:122, name:"操作结果1"},
    { id:1222, pId:122, name:"操作结果2"},
    { id:12221, pId:1222, name:"操作结果21"},
    { id:12222, pId:1222, name:"操作结果22"},
    { id:12223, pId:1222, name:"操作结果23"},
    { id:2, pId:0, name:"业务参数",open:true},
    { id:21, pId:2, name:"工单类型"},
    { id:22, pId:2, name:"监控类型"},
    { id:23, pId:22, name:"监控子类型1"},
    { id:24, pId:22, name:"监控子类型2"},
    { id:25, pId:24, name:"监控子子类型1"},
    { id:26, pId:24, name:"监控子子类型2"},
  ];
  var lastValue = '', nodeList = [], fontCss = {};
  function searchNode(e) {
    var zTree = $.fn.zTree.getZTreeObj("treeDemo");
    var value = $.trim(key.val());
    lastValue = value;
    //zTree.expandAll(true);
    $('#treeDemo').html("");
    $.fn.zTree.init($("#treeDemo"), setting, zNodes);
    if (value != "") {
      nodeList = zTree.getNodesByParamFuzzy("name", value);
    } else {
      nodeList = zTree.getNodesByParamFuzzy("name", "|||||||||||||||");
    }
    updateNodes(true);
  }
  var parentNode = [];
  function updateNodes(highlight) {
    var zTree = $.fn.zTree.getZTreeObj("treeDemo");
    parentNode = [];
    for( var i=0, l=nodeList.length; i 
 

效果图

以上所述是小编给大家介绍的ztree搜索中多级菜单展示不全的解决方法，希望对大家有所帮助，如果大家有任何疑问请给我留言，小编会及时回复大家的。在此也非常感谢大家对脚本之家网站的支持！