有时上网查资料,看到别人的博客上有关键字旋转的效果,觉得蛮不错的。于是网上搜索了一下它的实现,好吧,自己动手写写。
HTML:
Asp.net webform
Asp.net mvc
EF
Castle
Spring.net
NHibernate
WCF
WPF
AOP
IoC
SQL
Javascript
Jquery
KendoUI
CSS:
#div1{height:400px;width:450px; position:relative; margin:10px auto;}
#div1 a{position:absolute;top:0px;left:0px;font-weight:bold;padding:3px 6px; color:black; text-decoration: none;}
#div1 a:hover{border:1px solid #eee;background:#ccc;border-radius:5px;}
既然是关键字,我觉得给他们加上不同的颜色才够酷。初始化一个数组存放颜色值,然后再随机分配给各个标签。
var colors = ["#FF60AF","#9F35FF","#FF2D2D","#6C6C6C","#003D79","#00AEAE","#019858"];
var rand = Math.ceil(Math.random()*6);
aA[i].style.color=colors[rand];
JS:
var radius = 100;
var dtr = Math.PI/180;
var d=300;
var mcList = [];
var active = false;
var lasta = 1;
var lastb = 1;
var distr = true;
var tspeed=2;
var size=250;
var mouseX=0;
var mouseY=0;
var howElliptical=1;
var aA=null;
var oDiv=null;
window.onload=function ()
{
var i=0;
var oTag=null;
oDiv=document.getElementById('div1');
aA=oDiv.getElementsByTagName('a');
for(i=0;i
var colors = ["#FF60AF","#9F35FF","#FF2D2D","#6C6C6C","#003D79","#00AEAE","#019858"];
var rand = Math.ceil(Math.random()*6);
aA[i].style.color=colors[rand];
oTag={};
oTag.offsetWidth=aA[i].offsetWidth;
oTag.offsetHeight=aA[i].offsetHeight;
mcList.push(oTag);
}
sineCosine( 0,0,0 );
positionAll();
oDiv.onmouseover=function ()
{
active=true;
};
oDiv.onmouseout=function ()
{
active=false;
};
oDiv.onmousemove=function (ev)
{
var oEvent=window.event || ev;
mouseX=oEvent.clientX-(oDiv.offsetLeft+oDiv.offsetWidth/2);
mouseY=oEvent.clientY-(oDiv.offsetTop+oDiv.offsetHeight/2);
mouseX/=5;
mouseY/=5;
};
setInterval(update, 10);
};
function update()
{
var a;
var b;
if(active)
{
a = (-Math.min( Math.max( -mouseY, -size ), size ) / radius ) * tspeed;
b = (Math.min( Math.max( -mouseX, -size ), size ) / radius ) * tspeed;
}
else
{
a = lasta * 0.98;
b = lastb * 0.98;
}
lasta=a;
lastb=b;
if(Math.abs(a)<=0.01 && Math.abs(b)<=0.01)
{
return;
}
var c=0;
sineCosine(a,b,c);
for(var j=0;j
var rx1=mcList[j].cx;
var ry1=mcList[j].cy*ca+mcList[j].cz*(-sa);
var rz1=mcList[j].cy*sa+mcList[j].cz*ca;
var rx2=rx1*cb+rz1*sb;
var ry2=ry1;
var rz2=rx1*(-sb)+rz1*cb;
var rx3=rx2*cc+ry2*(-sc);
var ry3=rx2*sc+ry2*cc;
var rz3=rz2;
mcList[j].cx=rx3;
mcList[j].cy=ry3;
mcList[j].cz=rz3;
per=d/(d+rz3);
mcList[j].x=(howElliptical*rx3*per)-(howElliptical*2);
mcList[j].y=ry3*per;
mcList[j].scale=per;
mcList[j].alpha=per;
mcList[j].alpha=(mcList[j].alpha-0.6)*(10/6);
}
doPosition();
depthSort();
}
function depthSort()
{
var i=0;
var aTmp=[];
for(i=0;i
aTmp.push(aA[i]);
}
aTmp.sort
(
function (vItem1, vItem2)
{
if(vItem1.cz>vItem2.cz)
{
return -1;
}
else if(vItem1.cz
return 1;
}
else
{
return 0;
}
}
);
for(i=0;i
aTmp[i].style.zIndex=i;
}
}
function positionAll()
{
var phi=0;
var theta=0;
var max=mcList.length;
var i=0;
var aTmp=[];
var oFragment=document.createDocumentFragment();
//随机排序
for(i=0;i
aTmp.push(aA[i]);
}
aTmp.sort
(
function ()
{
return Math.random()<0.5?1:-1;
}
);
for(i=0;i
oFragment.appendChild(aTmp[i]);
}
oDiv.appendChild(oFragment);
for( var i=1; i
{
phi = Math.acos(-1+(2*i-1)/max);
theta = Math.sqrt(max*Math.PI)*phi;
}
else
{
phi = Math.random()*(Math.PI);
theta = Math.random()*(2*Math.PI);
}
//坐标变换
mcList[i-1].cx = radius * Math.cos(theta)*Math.sin(phi);
mcList[i-1].cy = radius * Math.sin(theta)*Math.sin(phi);
mcList[i-1].cz = radius * Math.cos(phi);
aA[i-1].style.left=mcList[i-1].cx+oDiv.offsetWidth/2-mcList[i-1].offsetWidth/2+'px';
aA[i-1].style.top=mcList[i-1].cy+oDiv.offsetHeight/2-mcList[i-1].offsetHeight/2+'px';
}
}
function doPosition()
{
var l=oDiv.offsetWidth/2;
var t=oDiv.offsetHeight/2;
for(var i=0;i
aA[i].style.left=mcList[i].cx+l-mcList[i].offsetWidth/2+'px';
aA[i].style.top=mcList[i].cy+t-mcList[i].offsetHeight/2+'px';
aA[i].style.fontSize=Math.ceil(12*mcList[i].scale/2)+8+'px';
aA[i].style.filter="alpha(opacity="+100*mcList[i].alpha+")";
aA[i].style.opacity=mcList[i].alpha;
}
}
function sineCosine( a, b, c)
{
sa = Math.sin(a * dtr);
ca = Math.cos(a * dtr);
sb = Math.sin(b * dtr);
cb = Math.cos(b * dtr);
sc = Math.sin(c * dtr);
cc = Math.cos(c * dtr);
}
最后看下效果: