googlesamples之easypermissions使用

使用

1. app/build.gradle

dependencies {
    compile 'pub.devrel:easypermissions:0.3.0'
}

2. 在Activity / Fragment实现PermissionCallbacks，回调方法：

@Override
public void onPermissionsGranted(int requestCode, List list) {
    // Some permissions have been granted
    // ...
    LogUtil.d("Some permissions have been granted=" + requestCode);
}
@Override
public void onPermissionsDenied(int requestCode, List list) {
    // Some permissions have been denied
    // ...
    LogUtil.d("Some permissions have been denied=" + requestCode);
}

3. 在需要使用到权限之前调用methodRequiresTwoPermission方法，如相机和发送短信：

@AfterPermissionGranted(1010)
private void methodRequiresTwoPermission() {
    String[] perms = {Manifest.permission.CAMERA, SEND_SMS};
    if (EasyPermissions.hasPermissions(this, perms)) {
        // Already have permission, do the thing
        // ...
        LogUtil.d("Already have permission, do the thing");
    } else {
        // Do not have permissions, request them now
        LogUtil.d("Do not have permissions, request them now");
        EasyPermissions.requestPermissions(this, "camera_and_send_sms", 1010, perms);
    }
}

4. 还是要授权回调：

@Override
public void onRequestPermissionsResult(int requestCode, String[] permissions, int[] grantResults) {
    super.onRequestPermissionsResult(requestCode, permissions, grantResults);
    // Forward results to EasyPermissions
    EasyPermissions.onRequestPermissionsResult(requestCode, permissions, grantResults, this);
}

这样就over了。

源码地址

https://github.com/googlesamples/easypermissions ，点击底部「阅读原文」直达。

一点思考

就在《Android 6.0 RuntimePermission》文章里，我对Android 6.0 运行权限做了个简单封装，但没有考虑到Fragment使用和勾上不再询问应该去setting，还一个问题，封装只是针对单个权限，推荐官方easypermissions库，来看看easypermissions是如何解决我未考虑的问题。

Fragment使用

直接提供了Fragment可以调用的方法：

@SuppressLint("NewApi")
public static void requestPermissions(@NonNull Fragment fragment,
                                      @NonNull String rationale,
                                      @StringRes int positiveButton,
                                      @StringRes int negativeButton,
                                      int requestCode,
                                      @NonNull String... perms) {
    if (hasPermissions(fragment.getContext(), perms)) {
        notifyAlreadyHasPermissions(fragment, requestCode, perms);
        return;
    }
    if (shouldShowRationale(fragment, perms)) {
        RationaleDialogFragmentCompat
                .newInstance(positiveButton, negativeButton, rationale, requestCode, perms)
                .show(fragment.getChildFragmentManager(), DIALOG_TAG);
    } else {
        fragment.requestPermissions(perms, requestCode);
    }
}

不再询问去setting

我在《Android 6.0 RuntimePermission》说当勾上“不再询问”，只能选择拒绝，再次进入，shouldShowRequestPermissionRationale方法始终false，当onPermissionsDenied方法回调时，肯定是都是拒绝，再根据shouldShowRequestPermissionRationale方法不就知道是否勾上了“不再询问”，我咋没有想到这点呢：

@Override
public void onPermissionsDenied(int requestCode, List perms) {
    Log.d(TAG, "onPermissionsDenied:" + requestCode + ":" + perms.size());

    // (Optional) Check whether the user denied any permissions and checked "NEVER ASK AGAIN."
    // This will display a dialog directing them to enable the permission in app settings.
    if (EasyPermissions.somePermissionPermanentlyDenied(this, perms)) {
        new AppSettingsDialog.Builder(this).build().show();
    }
}

@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);

    if (requestCode == AppSettingsDialog.DEFAULT_SETTINGS_REQ_CODE) {
        // Do something after user returned from app settings screen, like showing a Toast.
        Toast.makeText(this, R.string.returned_from_app_settings_to_activity, Toast.LENGTH_SHORT)
                .show();
    }
}

EasyPermissions的somePermissionPermanentlyDenied方法，就是根据shouldShowRequestPermissionRationale方法判断是否勾上了“不再询问”。

public static boolean somePermissionPermanentlyDenied(@NonNull Activity activity,
                                                      @NonNull List deniedPermissions) {
    for (String deniedPermission : deniedPermissions) {
        if (permissionPermanentlyDenied(activity, deniedPermission)) {
            return true;
        }
    }
    return false;
}
public static boolean permissionPermanentlyDenied(@NonNull Activity activity,
                                                  @NonNull String deniedPermission) {
    return !shouldShowRequestPermissionRationale(activity, deniedPermission);
}

跳转setting代码：

Intent intent = new Intent(Settings.ACTION_APPLICATION_DETAILS_SETTINGS);
Uri uri = Uri.fromParts("package", mContext.getPackageName(), null);
intent.setData(uri);
// Start for result
//noinspection NewApi The Builder constructor prevents this
startForResult(intent);

封装只针对单个权限

我应该封装多个权限，多权限是个数组，如果只有一个元素，不就是单个权限嘛！

转自：http://mp.weixin.qq.com/s/RKFP6rAfWuNcaATzxDmFlQ