初级算法-数组-从排序数组中删除重复项

LeetCode还是很人性化的  用到什么算法竟然还会提示并有百度百科的链接  此题用到了原地算法，就是输出结果覆盖输入结果，节省空间，附上代码，C语言，代码写的渣，还参考了网上的答案，如有哪里需要改进还请斧正！

#include 
int removeDuplicates(int* nums, int numsSize)
{
    int pre = 0, cur = 0;
    if (numsSize == 0)
        return 0;
    while (cur < numsSize)
    {
        if (nums[pre] == nums[cur])
        {
            cur++;
        }
        else
        {
            nums[++pre] = nums[cur++];
        }
    }
    return pre + 1;
}
int main()
{
    int nums[1000];
    int num, i = 0;
    while (~scanf("%d", &num))
    {
        nums[i] = num;
        i++;
    }
    removeDuplicates(nums, i);
}

https://blog.csdn.net/lizhidefengzi/article/details/70196058 在大佬博客中又学到了新姿势  c++11又有了for的新用法

And to not need the !i check in the loop:

int removeDuplicates(vector& nums) {
    int i = !nums.empty();
    for (int n : nums)
        if (n > nums[i-1])
            nums[i++] = n;
    return i;
}

And to not need the !i check in the loop:

int removeDuplicates(vector& nums) {
    int i = !nums.empty();
    for (int n : nums)
        if (n > nums[i-1])
            nums[i++] = n;
    return i;
}