题目链接
线段树的应用,区间更新(不用更新到底,更新到终止节点就行,查询时再将所涉及的节点信息push_down下来),颜色的数量用一个数组记录下来就行
#include
#include
#include
#include
#define lson tree[root].ls
#define rson tree[root].rs
using namespace std;
const int maxn = 100000;
struct node
{
int l, r;
int ls, rs;
int sta[4];
int up;
} tree[maxn*2+100];
int nCount = 1;
void build(int root, int l, int r)
{
tree[root].l = l;
tree[root].r = r;
if(l==r)
{
tree[root].sta[1] = 1;
tree[root].sta[2] = 0;
tree[root].sta[3] = 0;
tree[root].up = 0;
lson = 0;
rson = 0;
}
else
{
int mid = (l+r)/2;
lson = ++nCount;
build(lson, l, mid);
rson = ++nCount;
build(rson, mid+1, r);
for(int i=1; i<=3; i++)
tree[root].sta[i] = tree[lson].sta[i] + tree[rson].sta[i];
tree[root].up = 0;
}
}
void push_down(int root)
{
if(!tree[root].up) return;
for(int i=1; i<=3; i++)
tree[root].sta[i] = 0;
tree[root].sta[tree[root].up] = (tree[root].r-tree[root].l+1);
tree[lson].up = tree[rson].up = tree[root].up;
tree[root].up = 0;
}
void update(int root, int l, int r, int up)
{
if(tree[root].l==l && tree[root].r==r)
{
tree[root].up = up;
}
else
{
push_down(root);
int mid = (tree[root].l+tree[root].r)/2;
if(r<=mid) update(lson, l, r, up);
else if(l>=(mid+1)) update(rson, l, r, up);
else
{
update(lson, l, mid, up);
update(rson, mid+1, r, up);
}
push_down(lson);
push_down(rson);
for(int i=1; i<=3; i++)
tree[root].sta[i] = tree[lson].sta[i] + tree[rson].sta[i];
}
}
void query(int root, int l, int r, int* ans)
{
push_down(root);
if(tree[root].l==l && tree[root].r==r)
{
for(int i=1; i<=3; i++)
ans[i] += tree[root].sta[i];
}
else
{
int mid = (tree[root].l+tree[root].r)/2;
if(r<=mid) query(lson, l, r, ans);
else if(l>=(mid+1)) query(rson, l, r, ans);
else
{
query(lson, l, mid, ans);
query(rson, mid+1, r, ans);
}
}
}
int main()
{
int t, n, q, tt=1;
int x, y, z;
int ans[4], sum;
scanf("%d", &t);
while(t--)
{
scanf("%d%d", &n, &q);
nCount = 1;
build(1, 1, n);
for(int i=0; iscanf("%d%d%d", &x, &y, &z);
update(1, x, y, z);
}
memset(ans, 0, sizeof(ans));
query(1, 1, n, ans);
sum = 0;
for(int i=1; i<=3; i++)
sum += ans[i]*(i);
printf("Case %d: The total value of the hook is %d.\n", tt++, sum);
}
return 0;
}