leetcode 258. Add Digits

leetcode 258. Add Digits

Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.

For example:

Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.

Follow up:
Could you do it without any loop/recursion in O(1) runtime?

复杂度

 O(1)

代码

public class Solution {
    public int addDigits(int num) {
            while(num>9){

                int n=0;                
                while(num>9){

                    n=n+num%10;
                    num=num/10;
                }
               num=n+num%10;
           }
           return num;
    }

}

说明

1,以上是我的解法,为啥感觉时间复杂度不是O(1),但是被Accept了。
2,关于(n-1)%9+1的解法木有看懂!

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