20162312张家铖 查找课堂测试补分博客

题目要求：

• 1 用JDB或IDEA单步跟踪在下列数据中（3 8 12 34 54 84 91 110）查找45和54的过程，对比使用顺序查找和二分查找的执行过程
• 2提交测试找到或找不到那一步的截图，要全屏，包含自己的学号信息

• 3课下把代码推送到代码托管平台

  实验过程：

调用Searching中的binarySearch和linearSearch方法，然后再进行强制类型转换，转为Integer类型后查找45和54，打印出45、54是否找到

关键代码：

---

Searching：

import java.util.ArrayList;
import java.util.HashMap;

/**
 * Created by zjc  on 2017/11/6.
 */
public class Searching {

    public static Comparable linearSearch(Comparable[] data, Comparable target) {
        Comparable result = null;
        int index = 0;

        while (result == null && index < data.length) {
            if (data[index].compareTo(target) == 0)
                result = data[index];
            index++;
        }
        return result;
    }

    public static Comparable binarySearch(Comparable[] data, Comparable target) {
        Comparable result = null;
        int first = 0, last = data.length - 1, mid;

        while (result == null && first <= last) {
            mid = (first + last) / 2;
            if (data[mid].compareTo(target) == 0)
                result = data[mid];
            else if (data[mid].compareTo(target) > 0)
                last = mid - 1;
            else
                first = mid + 1;
        }
        return result;
    }



    public static int insertionSearch(int a[], int value,
                                      int low, int high)
    {
        int cp = low + (value - a[low]) / (a[high] - a[low]) * (high - low);
        if (a[cp] == value)
            return a[cp];
        if (a[cp] > value)
            return insertionSearch(a, value, low, cp - 1);
        if (a[cp] < value) ;
        return insertionSearch(a, value, cp + 1, high);

    }

    final int max_size = 20;



    public Integer FibonacciSearch(Integer a[], Integer key)
    {
        int low = 0;

        int high = a.length - 1;


        int[] F = new int[max_size];

        F[0] = 1;

        F[1] = 1;

        for (int i = 2; i < max_size; ++i)

            F[i] = F[i - 1] + F[i - 2];


        int h = 0;
        while (a.length > F[h] - 1)
            h++;

        Integer[] temp = new Integer[F[h] - 1];
        for (int j = 0; j < a.length; j++)
            temp[j] = a[j];

        for (int i = a.length; i < F[h] - 1; i++)
            temp[i] = a[a.length - 1];

        while (low <= high)
        {
            int mid = low + F[h - 1] - 1;

            if (key < temp[mid])
            {
                high = mid - 1;

                h = h-1;
            } else if (key > temp[mid])
            {
                low = mid + 1;

                h = h-2;

            }
            else
                {
                if (mid < a.length)

                    return mid;

                else

                    return a.length - 1;

            }
        }
        return null;
    }

    public static Comparable binarySearchTree(Comparable [] data, Comparable target){
        Comparable result = null;
        LinkedBinarySearchTree tree = new LinkedBinarySearchTree();
        for (int i = 0;i< data.length;i ++){
            tree.add(data[i]);
        }
        if (tree.find(target) == target)
            result = target;
        return result;
    }
    public static class blockSearch {


        private int[] index;
        private ArrayList[] list;

        public void blockSearch(int[] index, int i, int i1) {
            if (index != null && index.length != 0) {
                this.index = index;
                this.list = new ArrayList[index.length];

                for (i = 0; i < list.length; i++) {
                    list[i] = new ArrayList();
                }
            } else {
                throw new Error("index cannot be null or empty");
            }
        }
    }


    public int hashSearch(int[] data, int z)
    {
        boolean result = false;

        HashMap cop = new HashMap();

        for(int c = 0; c

test

/**
 * Created by zjc on 2017/11/6.
 */
public class searchtest {
    public static void main(String[] args) {
        int[] A1 = {2312, 2, 5, 8, 95, 3, 6, 5, 4,7,3,2, 6, 7};
        Integer[] A2 = {2, 2, 3, 5,4,2,6,8,435, 5, 6, 6, 7, 8, 95, 2312};

        Searching searching = new Searching();
        System.out.println(searching.hashSearch(A1, 6));
        System.out.println(searching.FibonacciSearch(A2,95));
        System.out.println(searching.insertionSearch(A1,8,2,0));
        System.out.println(searching.binarySearchTree(A2,8));

    }
}

单步跟踪截图：