request.getRequestURL()和request.getRequestURI()

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先申明,我是自己琢磨出来的,不知道对不对!!
但是,我想应该不会有太大的出入的!
getRequestURI()就相当于你在写一个JSP页面的时候会有这样的东西"action='/WebRoot/xxx'"这个方法就是获得'/WebRoot/xxx',也就是说它会得到一个相对地址
而getRequestURL()会得到一个完整的URL地址,也就是绝对的绝对地址

 

 

Request.getRequestURL返回的是请求的全部，包括Http协议，端口号，servlet名字和映射路径，但它不包含请求参数。
request.getRequestURI得到的是request URL的部分值，并且web容器没有decode过的

Java code

   
   
   
   

    
    
    
    
    
    
    
    getRequestURL：

    
    
    
    public
    
    
    
     java.lang.StringBuffer getRequestURL()
Reconstructs the URL the client used to make the request. The returned URL contains a protocol, server name, port number, and server path, but it does not include query string parameters. 

Because 
    
    
    
    this
    
    
    
     method returns a StringBuffer, not a string, you can modify the URL easily, 
    
    
    
    for
    
    
    
     example, to append query parameters. 

This method is useful 
    
    
    
    for
    
    
    
     creating redirect messages and 
    
    
    
    for
    
    
    
     reporting errors. 

Returns: 
a StringBuffer object containing the reconstructed URL

getRequestURI：

    
    
    
    public
    
    
    
     java.lang.String getRequestURI()
Returns the part of 
    
    
    
    this
    
    
    
     request
    
    
    
    '
    
    
    
    s URL from the protocol name up to the query string in the first line of the HTTP request. The web container does not decode this String. For example: 
    
    
    
    

    
    
    
    First line of HTTP request     Returned Value
POST 
    
    
    
    /
    
    
    
    some
    
    
    
    /
    
    
    
    path.html HTTP
    
    
    
    /
    
    
    
    1.1
    
    
    
             
    
    
    
    /
    
    
    
    some
    
    
    
    /
    
    
    
    path.html 
GET http:
    
    
    
    //
    
    
    
    foo.bar/a.html HTTP/1.0         /a.html 
    
    
    
    

    
    
    
    HEAD 
    
    
    
    /
    
    
    
    xyz
    
    
    
    ?
    
    
    
    a
    
    
    
    =
    
    
    
    b HTTP
    
    
    
    /
    
    
    
    1.1
    
    
    
             
    
    
    
    /
    
    
    
    xyz 
To reconstruct an URL with a scheme and host, use HttpUtils.getRequestURL(javax.servlet.http.HttpServletRequest). 
Returns: 
a String containing the part of the URL from the protocol name up to the query string 
See Also: 
HttpUtils.getRequestURL(javax.servlet.http.HttpServletRequest)


   
   
   
   

request.getRequestURI() /jqueryWeb/resources/request.jsp
request.getRequestURL() http://localhost:8080/jqueryWeb/resources/request.jsp
request.getContextPath()/jqueryWeb
request.getServletPath()/resources/request.jsp


注： resources为WebContext下的目录名
      jqueryWeb 为工程名