LeeCode-Merge Sorted Array

Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.

Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.

 

 1 void merge(int* nums1, int m, int* nums2, int n) 
 2 {
 3      int i=0;
 4     if(m==0&&n!=0)
 5     {
 6         while(i<n)
 7         {
 8             nums1[i]=nums2[i];
 9             i++;
10         }
11         return ;
12     }
13     if(n==0)
14         return ;
15     
16     int *TempArray;
17 
18     TempArray=(int*)malloc(sizeof(int)*(m+n));
19 
20     int L=0;
21     int k1=0,k2=0;
22     while(k1<m&&k2<n)
23     {
24         if(nums1[k1]>=nums2[k2])
25         {
26             TempArray[L++]=nums2[k2++];
27         }
28         else
29         {
30             TempArray[L++]=nums1[k1++];
31         }
32     }
33 
34 
35     if(k1==m)
36     {
37         while(k2<n)
38         {
39             TempArray[L++]=nums2[k2++];
40         }
41     }
42 
43     if(k2==n)
44     {
45         while(k1<m)
46         {
47             TempArray[L++]=nums1[k1++];
48         }
49     }
50 
51 
52 
53     for(i=0;i<m+n;i++)
54     {
55         nums1[i]=TempArray[i];
56     }
57 
58     free(TempArray);
59 
60 }