软工第二次作业--熟悉使用工具

熟悉使用工具


GIT地址 https://github.com/Ayanotc/AchaoCalculator
GIT用户名                                               Ayanotc
学号后五位                                                61420
博客地址 https://www.cnblogs.com/ayanotc/
作业链接 https://www.cnblogs.com/ChildishChange/p/10398212.html

1、环境配置

VS 和 GIT

软工第二次作业--熟悉使用工具_第1张图片

 

 

2、代码实现

题目要求:

软工第二次作业--熟悉使用工具_第2张图片

 

 

设计思路:

  • 假期的时候就写过一个计算器的程序,其中就包含了混合四则运算,所以就想要另外换一种思路,于是我就想到了利用switch函数来实现这个功能。
    • 首先运算中最多会出现四个数字三个运算符,所以我想把他们单独利用随机数产生;
    • 同时利用随机数来决定运算符的个数;
  软工第二次作业--熟悉使用工具_第3张图片
    •  通过对运算符数字化来进行选择
 
  软工第二次作业--熟悉使用工具_第4张图片 
 

 

    • 将题目写入文件(添加在最后面 )

软工第二次作业--熟悉使用工具_第5张图片

 

 

 

软工第二次作业--熟悉使用工具_第6张图片

 

 

 

    • 结果:

 

 软工第二次作业--熟悉使用工具_第7张图片

 

 软工第二次作业--熟悉使用工具_第8张图片

 

 

使用git提交:

 

       经过多次尝试,并向同学请教之后终于成功提交了!(过程太过艰辛,在这方面耗费的精力远远大于写代码,耗时太久不便详述)

 

测试过程:

 

      问题1:一开始忽视了结果不能出现小数和分数这个问题(由于使用的是int 类型定义并未显示出错误;)

      解决:  之后有附加个函数进行改正;此处体现出了函数功能模块化的优点。

 

      问题2:函数功能还是太过臃肿,有相同功能的部分还是没能成功分离出去,代码重复度高;

      解决:  由于优化过程中频频报错暂未解决。

 

   

 


3、感想

这次作业的代码部分并不难,都是曾经写过的程序,但是关于GitHub使用还是不懂,尝试了很多次也上网查了很多教程,暂时还都没有成功。还是需要去请教一下已经成功的同学如何去使用。

 

后记:今天终于成功了!自己总会有难以解决的问题,在经过独自大量努力后还无法解决一定要即使向他人求助,否则会在这方面浪费很多时间!

 

 

 


代码:

#include 
#include 
#include 

using namespace std;

char Calculator1(int T1)    //选择运算符
{
    char Oper1;

    switch (T1)
    {
    case 0: Oper1 = '+'; break;
    case 1: Oper1 = '-'; break;
    case 2: Oper1 = '*'; break;
    case 3: Oper1 = '/'; break;
    default: Oper1 = '+';
        break;
    }

    return Oper1;
}
char Calculator2(int T2)    //选择运算符
{
    char Oper2;

    switch (T2)
    {
    case 0: Oper2 = '+'; break;
    case 1: Oper2 = '-'; break;
    case 2: Oper2 = '*'; break;
    case 3: Oper2 = '/'; break;
    default: Oper2 = '+';
        break;
    }

    return Oper2;
}
char Calculator3(int T3)    //选择运算符
{
    char Oper3;

    switch (T3)
    {
    case 0: Oper3 = '+'; break;
    case 1: Oper3 = '-'; break;
    case 2: Oper3 = '*'; break;
    case 3: Oper3 = '/'; break;
    default: Oper3 = '+';
        break;
    }

    return Oper3;
}

int division(int a, int b)    //除法整除
{
    if (a % b != 0)
    {
        int c = 0;
        do {
            c = a % b;
            a-= c;
        } while (a% b == 0);
    }
    return a;
}

int Sum()
{
    int A = 0, B = 0, C = 0 , D = 0 ;    //计算数字
    int Operate_1 = 0, Operate_2 = 1, Operate_3 = 2;    //运算符
    char  Oper1, Oper2, Oper3;
    int Temp_x = 0;    //运算符个数
    int sum = 0;  //结果

    A = rand() % 100 + 1;     //计算数字
    B = rand() % 100 + 1;
    C = rand() % 100 + 1;
    D = rand() % 100 + 1;

    Operate_1 = rand() % 4;     //运算符
    Operate_2 = rand() % 4;
    Operate_3 = rand() % 4;

    Temp_x = rand() % 2 + 2;    //运算符个数


    ofstream outfile;    // 以写模式打开文件
    outfile.open("afile.txt", ios::app);


    if (Temp_x == 2)
    {
        int m = 0;

        if (Operate_1 == 2 || Operate_1 == 3)
        {    switch (Operate_1)
            {
            case 2:
                m = A * B; break;
            case 3:
                A = division(A, B);
                m = A / B; break;
            default: 0;
                break;
            }
        switch (Operate_2)
        {
        case 0:
            sum = m + C; break;
        case 1:
            sum = m - C; break;
        case 2:
            sum = m * C; break;
        case 3:
            m = division(m, C);
            sum = m / C; break;
        default: 0;
            break;
        }
        }
        else if (Operate_1 == 0 || Operate_1 == 1)
        {
            switch (Operate_2)
            {
            case 0:
                m = B + C; break;
            case 1:
                m = B - C; break;
            case 2:
                m = B * C; break;
            case 3:
                B = division(B, C);
                m = B / C; break;
            default: 0;
                break;
            }
            switch (Operate_1)
            {
            case 0:
                sum = A + m; break;
            case 1:
                sum = A - m; break;
            default: 0;
                break;
            }
        }
        Oper1=Calculator1(Operate_1);    Oper2 = Calculator2(Operate_2);
        cout << A << Oper1 << B << Oper2 << C << '=' << sum << endl;
        outfile << A << Oper1 << B << Oper2 << C << '=' << sum << endl;
            // 向文件写入用户输入的数据
    }
    else if (Temp_x == 3)
    {
        int j = 0, k = 0;
        if (Operate_2 == 0 || Operate_2==1)
        {
            switch (Operate_1)
            {
            case 0:
                j = A + B; break;
            case 1: 
                j = A - B; break;
            case 2:
                j = A * B; break;
            case 3:
                A = division(A, B);
                j = A / B; break;
            default: 0;
                break;
            }
            switch (Operate_3)
            {
            case 0:
                k = C + D; break;
            case 1:
                k = C - D; break;
            case 2:
                k = C * D; break;
            case 3:
                C = division(C, D);
                k = C / D; break;
            default: 0;
                break;
            }
            switch (Operate_2)
            {
            case 0:
                sum = j + k; break;
            case 1:
                sum = j - k; break;
                break;
            }
        }
        else if((Operate_2 == 2 || Operate_2 == 3)&&(Operate_1 == 0 || Operate_1 == 1))
        {
            switch (Operate_2)
            {
            case 2:
                j = B * C; break;
            case 3:
                B = division(B, C);
                j = B / C; break;
            default: 0;
                break;
            }
            switch (Operate_3)
            {
                case 0:
                    k = j + D; break;
                case 1:
                    k = j - D; break;
                case 2:
                    k = j * D; break;
                case 3:
                    j = division(j, D);
                    k = j / D; break;
            default:
                break;
            }
            switch (Operate_1)
            {
            case 0:
                sum = A + k;
            case 1:
                sum = A - k;
            default:0;
                break;
            }
        }
        else if ((Operate_1 == 0 || Operate_1 == 1)&&(Operate_2 == 0 || Operate_2 == 1))
        {
            switch (Operate_3)
            {
            case 0:
                k = C + D; break;
            case 1:
                k = C - D; break;
            case 2:
                k = C * D; break;
            case 3:
                C = division(C, D);
                k = C / D; break;
            default:0;
                break;
            }
            switch (Operate_1)
            {
            case 0:
                j = A + B; break;
            case 1:
                j = A - B; break;
            default:0;
                break;
            }
            switch (Operate_2)
            {
            case 0:
                sum = j + k; break;
            case 1:
                sum = j - k;
            default:
                break;
            }
        }
        else if ((Operate_2 == 2 || Operate_2 == 3)&&(Operate_1 == 2 || Operate_1 == 3))
        {
        switch (Operate_1)
        {
        case 2:
            j = A * B; break;
        case 3:
            A = division(A, B);
            j = A / B; break;
        default:
            break;
        }
        switch (Operate_2)
        {
        case 2:
            k = j * C; break;
        case 3:
            j = division(j, C);
            k = j / C; break;
        default:
            break;
        }
        switch (Operate_3)
        {
        case 0:
            sum = k + D; break;
        case 1:
            sum = k - D; break;
        case 2:
            sum = k * D; break;
        case 3:
            k = division(k, D);
            sum = k / D; break;
        default:
            break;
        }
        }
        else 
        {
        switch (Operate_3)
        {
        case 0:
            k = C + D; break;
        case 1:
            k = C - D; break;
        case 2:
            k = C * D; break;
        case 3:
            C = division(C, D);
            k = C / D; break;
        default:0;
            break;
        }
        switch (Operate_2)
        {
        case 0:
            j = B + k; break;
        case 1:
            j = B - k; break;
        case 2:
            j = B * k; break;
        case 3:
            B = division(B, k);
            j = B / k; break;
        default:0;
            break;
        }
        switch (Operate_1)
        {case 0:
            sum = A + j; break;
        case 1:
            sum = A - j; break;
        case 2:
            sum = A * j; break;
        case 3:
            A = division(A, j);
            sum = A / j; break;
        default:0;
            break;
        }
        }
        
        Oper1 = Calculator1(Operate_1);    Oper2 = Calculator2(Operate_2);     Oper3 = Calculator3(Operate_3);
        cout << A << Oper1 << B << Oper2 << C << Oper3 << D << '=' << sum << endl;
        outfile << A << Oper1 << B << Oper2 << C << Oper3 << D << '=' << sum << endl;
    }

    outfile.close();

        return sum;
}

int main()
{
    srand((unsigned)time(NULL));

    int num = 0;

    cout << "出题数 : ";
    cin >> num;
    for (int i = 0; i < num; i++)
    {
        Sum();
        cout << endl;
    }

    return 0;
}

 

你可能感兴趣的:(软工第二次作业--熟悉使用工具)