python模拟登录qq邮箱

     前两天做一个任务，要写一个收取qq邮箱邮件的脚本。开始认为挺简单，后来发现还是有一些坑在里面。

    首先使用python尝试模拟登录qq邮箱，发现普通用户已经不能通过账号密码模拟登录qq邮箱了。要用到授权码。（具体查看qq邮箱账号设置） 首先打开qq邮箱生成授权码，然后模拟登录中使用此授权码登录。

• 接收服务器：

pop.exmail.qq.com(使用SSL，端口号995)

发送服务器：

smtp.exmail.qq.com(使用SSL，端口号465)

这是企业邮箱。个人邮箱的话服务器地址没有exmail，并且个人邮箱需要用到授权码。

#!/usr/bin/python
# -*- coding:utf-8 -*-

import poplib, pprint, email, sys, time, email, time, smtplib, imaplib
from datetime import datetime, timedelta, date
from email.mime.text import MIMEText  
from email.header import Header
#设置命令窗口输出使用UTF-8编码
reload(sys)
sys.setdefaultencoding( "utf-8" )


# 第三方 SMTP 服务  注意这是企业邮箱  如果是个人邮箱，密码要用授权码，服务器地址没有exmail
mail_smtp_host= "smtp.exmail.qq.com"  		# 设置smtp服务器  
mail_pop_host= "pop.exmail.qq.com"			# 设置pop服务器
mail_user= ""    		# 用户名  
mail_pass= ""  				# 口令,QQ邮箱是输入授权码，在qq邮箱设置 里用验证过的手机发送短信获得，不含空格 

'''
/*DISCRIPTION
 *	Decoding charsert
 * ARGUMENTS
 * 	string need be Decodinged
 * RETURN
 * NOTES
 */
'''
def Decoding(str):
	if(str[0][1] == None): return unicode(str[0][0], 'gb18030')
	else: return unicode(str[0][0], str[0][1])
	
'''
/*DISCRIPTION
 *	Send the mail to the unsubmit
 * ARGUMENTS
 * 	string need be Decodinged
 * RETURN
 * NOTES
 */
'''
def  SendEmail():
	sender = ''  
	receivers = ['']  # 接收邮件，可设置为你的QQ邮箱或者其他邮箱  
  
	message = MIMEText('a test for python', 'plain', 'utf-8')  
	message['From'] = Header("ppyy", 'utf-8')  
	message['To'] =  Header("you", 'utf-8')  
  
	subject = 'my test'  
	message['Subject'] = Header(subject, 'utf-8')  
	try:  
  		smtpObj = smtplib.SMTP_SSL(mail_smtp_host, 465)   
  		smtpObj.login(mail_user,mail_pass)    
  		smtpObj.sendmail(sender, receivers, message.as_string()) 
  		smtpObj.quit()  
  		print u"邮件发送成功"  
	except smtplib.SMTPException,e:  
  		print e  


def GetEmail():
	try:
		pp = poplib.POP3_SSL(mail_pop_host)
		pp.user(mail_user)
		pp.pass_(mail_pass)
		ret =pp.stat()
		print u"登录成功"
	except:
		print "can't connect to mailserver"

	#遍历邮件的标题
	# emailMsgNum, emailSize = pp.stat()
	# for i in xrange(1, emailMsgNum+1):
	# 	ret = pp.retr(i)
	# 	mail = email.message_from_string("\n".join(ret[1]))
	# 	subject = email.Header.decode_header(mail['subject'])
	# 	MailSubject 	= Decoding(subject)
	# 	print MailSubject  
		                
	ret = pp.retr(2)
	msg = email.message_from_string("\n".join(ret[1]))
	print msg.get_payload()

	# down = pp.retr(1)
	# print 'lines:', len(down)
	# for line in down[1]:
	#  	print line

	pp.quit()
GetEmail();