jquery ajaxSubmit 异步提交的简单实现

这篇文章主要介绍了jquery ajaxSubmit 异步提交的简单实现。需要的朋友可以过来参考下，希望对大家有所帮助
前台js

$("#nickForm").ajaxSubmit({
     type: "post",
     url: "http://localhost:8080/test/myspace.do?method=updateNick¶m=1",
     dataType: "json",
     success: function(result){
           //返回提示信息       
           alert(result.nickMsg);
     }
 });

后台封装：

public ActionForward toUpdateNickName(ActionMapping mapping, ActionForm form,
   HttpServletRequest request, HttpServletResponse response){
       PrintWriter pw = response.getWriter();
      JSONObject obj = new JSONObject();
      obj.put("nickMsg", "昵称修改成功！");
      pw.print(obj);
      pw.close();
}

详细出处参考：http://www.jb51.net/article/47391.htm