601. Human Traffic of Stadium

四层嵌套，I‘m’ fine，fuck you！

总之思想就是先把不到100的T了，然后重新给一个全表排序序号，你会发现，相邻的日期，id（或者日期）减去新排序rownum的值是相同的，然后相同的count超过3个的就是我们想要的值，总之属于暴力解题，幸亏性能过关了，so，就这样了

# Write your MySQL query statement below
set @rownum1:=0;
set @rownum2:=0;
select temp1.id,temp1.date,temp1.people
from (select count(*) as row_counts,diffnum
from (select t.*,t.id-t.row_num as diffnum
from (select a.*,
   @rownum1:=@rownum1+1 as row_num
  from (select * from stadium  where people>=100) a) t)s
group by diffnum) temp2
join
(select t.*,t.id-t.row_num as diffnum
 from (select a.*,
   @rownum2:=@rownum2+1 as row_num
     from (select * from stadium  where people>=100) a) t) temp1
on (temp1.diffnum=temp2.diffnum)
where temp2.row_counts>=3
order by temp1.date