C++代码实现GPS秒到UTC时间、北京时间的转换，本代码的前提是知道当前GPS秒和当前是星期几，特此写出来供大家学习交流；如果不知道是周几，可以参考我的另一篇博客如何求星期几的代码

如果不知道是周几，可以参考我的另一篇博客如何求星期几的代码，

链接为：https://blog.csdn.net/howe1233/article/details/82954768

#include
using namespace std;
const int t_error=18;   //the error between GPS time and UTC time  t_error=gps_t-utc_t;
void GPS2UTC(const int& gpstime,const int&dayofweek)
{
    int hour,minute,second;
    hour=(gpstime-dayofweek*86400-t_error)/3600;
    minute=((gpstime-dayofweek*86400-t_error)%3600)/60;
    second=((gpstime-dayofweek*86400-t_error)%3600)%60;
    cout<<"the UTC time is:"<     cout<     
}
void GPS2Beijing(const int& gpstime,const int&dayofweek)
{
    int hour,minute,second;
    hour=(gpstime-dayofweek*86400-t_error)/3600+8;//adding 8 hours is beijing time
    minute=((gpstime-dayofweek*86400-t_error)%3600)/60;
    second=((gpstime-dayofweek*86400-t_error)%3600)%60;
    cout<<"the Beijing time is:"<     cout<     
}
int main()
{
    int GPS_time,dayofweek;
    cin>>GPS_time>>dayofweek;
    GPS2UTC(GPS_time,dayofweek);
    GPS2Beijing(GPS_time,dayofweek);
    system("pause");
    return 0;
}