使用 java 进行文件拷贝 相信很多人都会用,不过效率上是否最好呢?最近看了看NIO决定试一试 java NIO 到底有什么性能的提升.
第一种方法:古老的方式
public
static
long
forJava(File f1,File f2)
throws
Exception{
long
time
=
new
Date().getTime();
int
length
=
2097152
;
FileInputStream in
=
new
FileInputStream(f1);
FileOutputStream out
=
new
FileOutputStream(f2);
byte
[] buffer
=
new
byte
[length];
while
(
true
){
int
ins
=
in.read(buffer);
if
(ins
==-
1
){
in.close();
out.flush();
out.close();
return
new
Date().getTime()
-
time;
}
else
out.write(buffer,
0
,ins);
}
}
方法的2参数分别是原始文件,和拷贝的目的文件.这里不做过多介绍.
实现方法很简单,分别对2个文件构建输入输出流,并且使用一个字节数组作为我们内存的缓存器, 然后使用流从f1 中读出数据到缓存里,在将缓存数据写到f2里面去.这里的缓存是2MB的字节数组
第2种方法:使用NIO中的管道到管道传输
public
static
long
forTransfer(File f1,File f2)
throws
Exception{
long
time
=
new
Date().getTime();
int
length
=
2097152
;
FileInputStream in
=
new
FileInputStream(f1);
FileOutputStream out
=
new
FileOutputStream(f2);
FileChannel inC
=
in.getChannel();
FileChannel outC
=
out.getChannel();
int
i
=
0
;
while
(
true
){
if
(inC.position()
==
inC.size()){
inC.close();
outC.close();
return
new
Date().getTime()
-
time;
}
if
((inC.size()
-
inC.position())
<
20971520
)
length
=
(
int
)(inC.size()
-
inC.position());
else
length
=
20971520
;
inC.transferTo(inC.position(),length,outC);
inC.position(inC.position()
+
length);
i
++
;
}
}
实现方法:在第一种实现方法基础上对输入输出流获得其管道,然后分批次的从f1的管道中像f2的管道中输入数据每次输入的数据最大为2MB
方法3:内存文件景象写(读文件没有使用文件景象,有兴趣的可以回去试试,,我就不试了,估计会更快)
public
static
long
forImage(File f1,File f2)
throws
Exception{
long
time
=
new
Date().getTime();
int
length
=
2097152
;
FileInputStream in
=
new
FileInputStream(f1);
RandomAccessFile out
=
new
RandomAccessFile(f2,
"
rw
"
);
FileChannel inC
=
in.getChannel();
MappedByteBuffer outC
=
null
;
MappedByteBuffer inbuffer
=
null
;
byte
[] b
=
new
byte
[length];
while
(
true
){
if
(inC.position()
==
inC.size()){
inC.close();
outC.force();
out.close();
return
new
Date().getTime()
-
time;
}
if
((inC.size()
-
inC.position())
<
length){
length
=
(
int
)(inC.size()
-
inC.position());
}
else
{
length
=
20971520
;
}
b
=
new
byte
[length];
inbuffer
=
inC.map(MapMode.READ_ONLY,inC.position(),length);
inbuffer.load();
inbuffer.get(b);
outC
=
out.getChannel().map(MapMode.READ_WRITE,inC.position(),length);
inC.position(b.length
+
inC.position());
outC.put(b);
outC.force();
}
}
实现方法:跟伤2个例子不一样,这里写文件流没有使用管道而是使用内存文件映射(假设文件f2在内存中).在循环中从f1的管道中读取数据到字节数组里,然后在像内存映射的f2文件中写数据.
第4种方法:管道对管道
public
static
long
forChannel(File f1,File f2)
throws
Exception{
long
time
=
new
Date().getTime();
int
length
=
2097152
;
FileInputStream in
=
new
FileInputStream(f1);
FileOutputStream out
=
new
FileOutputStream(f2);
FileChannel inC
=
in.getChannel();
FileChannel outC
=
out.getChannel();
ByteBuffer b
=
null
;
while
(
true
){
if
(inC.position()
==
inC.size()){
inC.close();
outC.close();
return
new
Date().getTime()
-
time;
}
if
((inC.size()
-
inC.position())
<
length){
length
=
(
int
)(inC.size()
-
inC.position());
}
else
length
=
2097152
;
b
=
ByteBuffer.allocateDirect(length);
inC.read(b);
b.flip();
outC.write(b);
outC.force(
false
);
}
}
这里实现方式与第3种实现方式很类似,不过没有使用内存影射.
下面是对49.3MB的文件进行拷贝的测试时间(毫秒)
Start Copy File... file size:50290KB
CopyFile:b1.rmvb mode:forChannel RunTime:3203
CopyFile:b1.rmvb mode:forImage RunTime:3328
CopyFile:b1.rmvb mode:forJava RunTime:2172
CopyFile:b1.rmvb mode:forTransfer RunTime:1406
End Copy File!