①给定一个数字列表,如何返回一个由每个数的平方构成的列表?给定【1,2,3,4,5】返回【1,4,9,16,25】
@Test
public void test1(){
Integer[] nums = new Integer[]{1,2,3,4,5};
Arrays.stream(nums).map((x) -> x * x).forEach(System.out::println);
}
②使用map和reduce计算流中有多少Employee
List employees = Arrays.asList(
new Employee("张三",18,9999.99),
new Employee("李四",58,5555.55),
new Employee("王五",26,3333.33),
new Employee("赵柳",36,6666.66),
new Employee("天琪",12,8888.88),
new Employee("天琪",12,8888.88));
@Test
public void test2(){
Optional reduce = employees.stream().map((e) -> 1).reduce(Integer::sum);
System.out.println(reduce.get());
}
③有三个类:
交易员类:
public class Trader {
private String name;
private String city;
@Override
public String toString() {
return "Trader{" +
"name='" + name + '\'' +
", city='" + city + '\'' +
'}';
}
public Trader(String name, String city) {
this.name = name;
this.city = city;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getCity() {
return city;
}
public void setCity(String city) {
this.city = city;
}
}
交易数据类:
public class Transaction {
private Trader trader;
private int year;
private int value;
@Override
public String toString() {
return "Transaction{" +
"trader=" + trader +
", year=" + year +
", value=" + value +
'}';
}
public Trader getTrader() {
return trader;
}
public void setTrader(Trader trader) {
this.trader = trader;
}
public int getYear() {
return year;
}
public void setYear(int year) {
this.year = year;
}
public int getValue() {
return value;
}
public void setValue(int value) {
this.value = value;
}
public Transaction(Trader trader, int year, int value) {
this.trader = trader;
this.year = year;
this.value = value;
}
}
一些交易数据:
public class TestTransaction {
List transactions = null;
@Before
public void before(){
Trader raoul = new Trader("Raoul", "Cambridge");
Trader mario = new Trader("Mario", "Milan");
Trader alan = new Trader("Alan", "Cambridge");
Trader brian = new Trader("Brian", "Cambridge");
transactions = Arrays.asList(
new Transaction(brian, 2011, 300),
new Transaction(raoul, 2012, 1000),
new Transaction(raoul, 2011, 400),
new Transaction(mario, 2012, 710),
new Transaction(mario, 2012, 700),
new Transaction(alan, 2012, 950)
);
}
}
要求:
1. 找出2011年发生的所有交易, 并按交易额排序(从低到高)
2. 交易员都在哪些不同的城市工作过?
3. 查找所有来自剑桥的交易员,并按姓名排序
4. 返回所有交易员的姓名字符串,按字母顺序排序
5. 有没有交易员是在米兰工作的?
6. 打印生活在剑桥的交易员的所有交易额
7. 所有交易中,最高的交易额是多少
8. 找到交易额最小的交易
答案:
//1. 找出2011年发生的所有交易, 并按交易额排序(从低到高)
@Test
public void test1(){
transactions.stream()
.filter((t) -> t.getYear() == 2011)
.sorted((t1, t2) -> Integer.compare(t1.getValue(), t2.getValue()))
.forEach(System.out::println);
}
//2. 交易员都在哪些不同的城市工作过?
@Test
public void test2(){
transactions.stream()
.map((t) -> t.getTrader().getCity())
.distinct()
.forEach(System.out::println);
}
//3. 查找所有来自剑桥的交易员,并按姓名排序
@Test
public void test3(){
transactions.stream()
.filter((t) -> t.getTrader().getCity().equals("Cambridge"))
.map(Transaction::getTrader)
.sorted((t1, t2) -> t1.getName().compareTo(t2.getName()))
.distinct()
.forEach(System.out::println);
}
//4. 返回所有交易员的姓名字符串,按字母顺序排序
@Test
public void test4(){
transactions.stream()
.map((t) -> t.getTrader().getName())
.sorted()
.forEach(System.out::println);
System.out.println("-----------------------------------");
String str = transactions.stream()
.map((t) -> t.getTrader().getName())
.sorted()
.reduce("", String::concat);
System.out.println(str);
System.out.println("------------------------------------");
transactions.stream()
.map((t) -> t.getTrader().getName())
.flatMap(TestTransaction::filterCharacter)
.sorted((s1, s2) -> s1.compareToIgnoreCase(s2))
.forEach(System.out::print);
}
public static Stream filterCharacter(String str){
List list = new ArrayList<>();
for (Character ch : str.toCharArray()) {
list.add(ch.toString());
}
return list.stream();
}
//5. 有没有交易员是在米兰工作的?
@Test
public void test5(){
boolean bl = transactions.stream()
.anyMatch((t) -> t.getTrader().getCity().equals("Milan"));
System.out.println(bl);
}
//6. 打印生活在剑桥的交易员的所有交易额
@Test
public void test6(){
Optional sum = transactions.stream()
.filter((e) -> e.getTrader().getCity().equals("Cambridge"))
.map(Transaction::getValue)
.reduce(Integer::sum);
System.out.println(sum.get());
}
//7. 所有交易中,最高的交易额是多少
@Test
public void test7(){
Optional max = transactions.stream()
.map((t) -> t.getValue())
.max(Integer::compare);
System.out.println(max.get());
}
//8. 找到交易额最小的交易
@Test
public void test8(){
Optional op = transactions.stream()
.min((t1, t2) -> Integer.compare(t1.getValue(), t2.getValue()));
System.out.println(op.get());
}