mysql 常用的统计语句

---

drop table if exists test;
create table test
select '2005-05-09' date,'胜' flag union all
select '2005-05-09','胜' union all
select '2005-05-09','负' union all
select '2005-05-09','负' union all
select '2005-05-10','胜' union all
select '2005-05-10','负' union all
select '2005-05-10','负';

drop table if exists test1;
create table test1
select date,
sum(case when flag='胜' then 1 else 0 end) win,
sum(case when flag='负' then 1 else 0 end) fail
from test
group by date;

drop table if exists yj;
create table yj
select '一月份' mon, 01  dep,10 yj union all
select '一月份' mon, 02  dep,10 yj union all
select '一月份' mon,  03  dep, 5 yj union all
select '二月份' mon,  02  dep, 8 yj union all
select '二月份' mon,  04  dep, 9 yj union all
select '三月份' mon,  03  dep, 8 yj;

drop table if exists dep;
create table dep
select '01' dep,'国内业务一部' dname union all
select '02' dep,'国内业务二部' dname union all
select '03' dep,'国内业务三部' dname union all
select '04' dep,'国际业务部' dname;

select a.dep,
max(case when b.mon='一月份' then b.yj else null end) yj1,
max(case when b.mon='二月份' then b.yj else null end) yj2,
max(case when b.mon='三月份' then b.yj else null end) yj3
from dep a
join yj b on a.dep=b.dep
group by a.dep;

drop table if exists A;
create table A
select 1  id,     28 score union all
select 2  id,     33 score union all
select 3  id,     33 score union all
select 4  id,     89 score union all
select 5  id,     99 score union all
select 6  id,     68 score union all
select 7  id,     68 score union all
select 8  id,     78 score union all
select 9  id,     88 score union all
select 10 id,    90 score;

select * from (
select t.*,@rank := @rank+1 rank
from
(select * from A order by score) t,(select @rank := 0) b
) c;

# rownum
drop table if exists emp;  
create table emp (empid int ,deptid int ,salary decimal(10,2) ); 
insert into emp values   
(1,10,5500.00),  
(2,10,4500.00),  
(3,20,1900.00),  
(4,20,4800.00),  
(5,40,6500.00),  
(6,40,14500.00),  
(7,40,44500.00),  
(8,50,6500.00),  
(9,50,7500.00);

# row_number() over (partition by col1 order by col2) 
select empid,
    deptid,
    salary,
    rank 
from (  
    select t.empid,
        t.deptid,
        t.salary,
        @rownum:=@rownum+1,  
        if(@pdept=t.deptid,@rank:=@rank+1,@rank:=1) as rank,  
        @pdept:=t.deptid
    from (   
        select empid,deptid,salary from emp order by deptid asc ,salary desc   
    ) t , 
    (select @rownum :=0 , @pdept := null ,@rank:=0) a  
) c ;

SELECT aa.totalAmount,
    aa.payAmount,
    aa.t_amount,
    if(@m=aa.s_month,@amt:=@amt+aa.t_amount,@amt:=aa.t_amount) t_amt,
    if(@m=aa.s_month,@pay:=@pay+aa.payAmount,@pay:=aa.payAmount) t_pay,
    @m:=DATE_ADD(aa.s_month,interval 1 MONTH) s_month
FROM (
SELECT DATE_FORMAT(dateISO,'%Y-%m-01') s_month,
    sum(totalAmount) totalAmount,
    sum(payAmount) payAmount,
    sum(totalAmount-payAmount) t_amount
FROM test a
GROUP BY DATE_FORMAT(dateISO,'%Y-%m-01')
ORDER BY 1 ASC
) aa,(SELECT @m:=null,@pay:=0,@amt:=0) t
;