c++ templat乱测

该上机实验环境 linux mint  IDE：qt5.11   代码复制到windows下vs2017报错，提示char* 类型不能直接赋值字符串

在linux mint下可以运行,测试目的：检验复制构造函数以及左移运算符在输出类对象方面的作用

#include 
#include<string.h>
using namespace std;

class mycoach
{
public:
    friend ostream & operator<<(ostream& out,mycoach&t);
    mycoach()
    {
        age=22;
        c_name=new char[1];
        strcpy(c_name,"");
    }

    mycoach(char * name,int age)
    {
        this->age=age;
        c_name=new char[strlen(name)+1];//never forgot allowa space
        strcpy(c_name,name);
    }

    mycoach(const mycoach &t)
    {
        this->age=t.age;
        strcpy(this->c_name,t.c_name);
    }

    ~mycoach()
    {
        if(c_name!=NULL)
        {
            delete [] c_name;
            c_name=NULL;
        }
    }

    mycoach& operator=(const mycoach& t)
    {
        if (c_name!=NULL)
        {
            delete[] c_name;
            age=22;
            c_name=NULL;
        }
        c_name=new char[strlen(t.c_name)+1];
        strcpy(c_name,t.c_name);
        age=t.age;
        return *this;//this is a pointer *this  is value
    }

    void print()
    {
        cout<<"hello~emma "<<this->c_name<<" emma "<<this->age<<" years old";
    }
private:
    char*name[32];
    char * c_name;
    int age;
};

ostream & operator<<(ostream& out,mycoach&t)
{
    out<<"大家好~我是:"<",今年"<endl;
}

int main()
{
    //
    mycoach cpc("陈培昌",22);
    mycoach fgf;
    fgf=cpc;
    cout<endl;
    mycoach fgf2("付高峰",30);
    fgf=fgf2;
    cout<endl;
    cout << "Hello World!" << endl;
    return 0;
}