2016-03-21-AppFiolo Interview questions

AppFolio, Inc.(NASDAQ:APPF)成立于2006年，总部位于美国加州圣巴巴拉，创始人为加州大学前计算机科学教授克劳斯·绍瑟尔(Klasu Schauser)和琼·沃克尔(Jon Walker)，是一家物业管理软件开发公司。

AppFolio creates complete, easy-to-use, cloud-based software for multiple vertical markets.

AppFolio Property Manager

General questions

1. How to know AppFilo? Why AppFilo?
2. introduce your projects and tech stacks
3. Node.js, which kind of framework you used ?

Tech questions

1. Tell me about the data schema and programming in PostgreSQL

2. What you did in MongoDB?

3. How to use the ElasticSearch in your project?

Coding questions

• Reverse the words in the string, without java.util method - split
  for example:
  Today is Monday March 21st=> 21st March Monday is Today

3/22/16 update

这个是更精炼的解法

import java.util.*;

public class ReverseString{
    public static String reverseWordsInString(String s) {
        StringBuilder res = new StringBuilder(); 
        int j = s.length();
        
        for (int i = s.length() - 1; i >= 0; i--) {
            if (s.charAt(i) == ' ') {
                j = i;
            } else if (i == 0 || s.charAt(i-1) == ' ') {
                
                if (res.length() != 0) {
                    res.append(' ');
                }
                res.append(s.substring(i,j));
            }
        }
        return res.toString();
    }
}
    

旧的解法，留个纪念

import java.util.*;

public class ReverseString{

    public static void main(String[] args) {

        String str = "Today     is Monday March 21st";
        System.out.println(str);
        System.out.print("=> " + reverseStr(str));
    }

    public static String reverseStr(String str) {
        // split string to multiple words
        LinkedList list = new LinkedList<>();
        
        // check the whitespace , split string by whitespace
        int n = str.length();
        int left = 0, right = 0; 
        int index = 0;

        for (int i=0; i < n; i++){
            right++;
            if(str.charAt(i) == ' ') {
                String temp = str.substring(left, right);
                list.add(index, temp); 
                left = right;
                index++;
            }
        }
           // add the last word int the string
        list.add(index, str.substring(left, right));

        StringBuilder sb = new StringBuilder();
        for (int j=list.size() -1; j >= 0; j--) {
           sb.append(list.get(j) + " " );
         }
        return sb.toString();
    }
}

• Update the code using OOP concept

class Meeting

end

class Interview

end

class DesignReview

end

class Scheduler

  def schedulable?(target, start_date, end_date)
    if target.is_a?(Meeting)
      return end_date - (start_date - 5.days) > 10.days
    elsif target.is_a?(Interview)
      return start_date > (end_date - 2.days)
    elsif target.is_a?(DesignReview)
      return (end_date + 10.days) - start_date > 15.days

    
    end
  end

end

targets = [ Meeting.new, Interview.new, DesignReview.new ]
scheduler = Scheduler.new

targets.each do |target|
  if scheduler.schedulable?(target, Clock.today, Clock.today + 10)
    puts "The #{target.class.name} can be scheduled"
  end
end

＃＃尾声
让面试官给推荐了一本书，
Agile Web Development with Rails 4 (Facets of Ruby) 1st Edition