题目来源
Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg"
, "add"
, return true.
Given "foo"
, "bar"
, return false.
Given "paper"
, "title"
, return true.
Note:
You may assume both s and t have the same length.
然后我想了一个非常弱的解决方案…遍历,两个哈希表来记录s到t,t到s的映射关系,假如关系不对,就返回false。虽然A了,但是还是有点乱…再想想。
class Solution {
public:
bool isIsomorphic(string s, string t) {
int n = s.size();
unordered_map map1;
unordered_map map2;
for (int i=0; i
然后实际上只需要记录当前字母前一次出现的位置就可以了,代码如下:
class Solution {
public:
bool isIsomorphic(string s, string t) {
int n = s.size();
vector m1(256, 0);
vector m2(256, 0);
for (int i=0; i