在java语言中,把数组转换成List集合,有个很方便的方法就是
List list = Arrays.asList("a","b","c");
如果你之前没有对返回来 list
进行操作(add,remove),那么就完美避开了这个坑。
list.add("d"); // list.remove(1);
System.out.println(list);
Exception in thread "main" java.lang.UnsupportedOperationException
at java.util.AbstractList.add(AbstractList.java:148)
at java.util.AbstractList.add(AbstractList.java:108)
疑问! 为什么会抛异常?
源码分析 Arrays.class
public class Arrays {
public static List asList(T... a) {
return new ArrayList<>(a);
}
/**
* @serial include
*/
private static class ArrayList extends AbstractList
implements RandomAccess, java.io.Serializable
{
private final E[] a;
ArrayList(E[] array) {
a = Objects.requireNonNull(array);
}
....
}
...
}
看源码才知道 Arrays.asList() 返回是 Arrays 中的一个私有内部类 java.util.Arrays.ArrayList
private static class ArrayList extends AbstractList implements RandomAccess, java.io.Serializable {
private static final long serialVersionUID = -2764017481108945198L;
private final E[] a;
ArrayList(E[] array) {
a = Objects.requireNonNull(array);
}
@Override
public int size() {
return a.length;
}
@Override
public Object[] toArray() {
return a.clone();
}
@Override
@SuppressWarnings("unchecked")
public T[] toArray(T[] a) {
int size = size();
if (a.length < size)
return Arrays.copyOf(this.a, size, (Class extends T[]>) a.getClass());
System.arraycopy(this.a, 0, a, 0, size);
if (a.length > size)
a[size] = null;
return a;
}
@Override
public E get(int index) {
return a[index];
}
@Override
public E set(int index, E element) {
E oldValue = a[index];
a[index] = element;
return oldValue;
}
@Override
public int indexOf(Object o) {
E[] a = this.a;
if (o == null) {
for (int i = 0; i < a.length; i++)
if (a[i] == null)
return i;
} else {
for (int i = 0; i < a.length; i++)
if (o.equals(a[i]))
return i;
}
return -1;
}
@Override
public boolean contains(Object o) {
return indexOf(o) != -1;
}
@Override
public Spliterator spliterator() {
return Spliterators.spliterator(a, Spliterator.ORDERED);
}
@Override
public void forEach(Consumer super E> action) {
Objects.requireNonNull(action);
for (E e : a) {
action.accept(e);
}
}
@Override
public void replaceAll(UnaryOperator operator) {
Objects.requireNonNull(operator);
E[] a = this.a;
for (int i = 0; i < a.length; i++) {
a[i] = operator.apply(a[i]);
}
}
@Override
public void sort(Comparator super E> c) {
Arrays.sort(a, c);
}
}
接着这个内部类java.util.Arrays.ArrayList
public abstract class AbstractList extends AbstractCollection implements List {
public boolean add(E e) {
add(size(), e);
return true;
}
public void add(int index, E element) {
throw new UnsupportedOperationException();
}
public E remove(int index) {
throw new UnsupportedOperationException();
}
public E set(int index, E element) {
throw new UnsupportedOperationException();
}
...
}
顺藤摸瓜接着往父类找,真相大白!
Arrays.asList() 返回是 Arrays 中的一个私有内部类
java.util.Arrays.ArrayList
而并非我们用的java.util.ArrayList
java.util.Arrays.ArrayList
内部类继承了 AbstractList并且没有重写 add() 、remove() 方法。 而
java.util.AbstractList
add() 、remove() 、set() 就负责抛出一个 UnsupportedOperationException() 异常
解决办法
再次 list = new ArrayList<>(list);
List list = Arrays.asList("a", "b", "c");
// java.util.ArrayList
list = new ArrayList<>(list);
list.add("d");
System.out.println(list);
[a, b, c, d]