Array.png
concat
let [arr1,arr2] = [[1,2,3],[3,4,5]];
let array = arr1.concat(arr2);
console.log(array,arr1,arr2);
// [1, 2, 3, 3, 4, 5] [1, 2, 3] [3, 4, 5]
// 也用做数组深拷贝（深复制，深克隆...）,该方法不会改变现有的数组，而仅仅会返回被连接数组的一个副本
join 数组转字符串
let [arr1,arr2] = [[1,2,4,5],[2,3]];
let str1 = arr1.join(arr2);
console.log(str1, arr1, arr2);
// 12,322,342,35 [1, 2, 4, 5] [2, 3]
let [arr3,arr4] = [['你'],['好']];
let str2 = arr3.join(arr4);
console.log(str2, arr3, arr4);
// 你 ["你"] ["好"]
let arr = new Array(3)
arr[0] = "George"
arr[1] = "John"
arr[2] = "Thomas"
console.log(arr.join(' '));
// George John Thomas
console.log(arr.join());
// George,John,Thomas
pop 删除并返回数组的最后一个元素
let arr = [1,2,3,4,5];
console.log(arr.pop(),arr);
//5 [1, 2, 3, 4]
push
let arr = [1,2,3,4];
console.log(arr.push(5),arr)
//5 [1, 2, 3, 4, 5]
reverse
let arr = [1,2,3,'n','m',{age:18,name:'hao'}]
console.log(arr.reverse(),arr);
//[{age: 18, name: "hao"}, "m", "n", 3, 2, 1] [{age: 18, name: "hao"}, "m", "n", 3, 2, 1]
shift
let arr = [1,2,3,4];
console.log(arr.shift(),arr)
// 1 [2, 3, 4]
slice
let arr = [1,2,3,4,5];
let str = 'abcdefg'
console.log(arr.slice(1,3),arr,str.slice(1,3),str);
// [2, 3] [1, 2, 3, 4, 5] "bc" "abcdefg"
// 既可以操作数组又可以操作字符串，并且不会修改原值
sort
let arr = [1,2,3,4,5,6,23,45,55];
console.log(arr.sort(),arr);
// [1, 2, 23, 3, 4, 45, 5, 55, 6] [1, 2, 23, 3, 4, 45, 5, 55, 6]
console.log(arr.sort((a,b)=> a-b ))
// [1, 2, 3, 4, 5, 6, 23, 45, 55]
let str = ['asd','dfg','daa','css','g','f'];
console.log(str.sort(), str.sort((a,b)=> b-a))
// ["asd", "css", "daa", "dfg", "f", "g"] ["asd", "css", "daa", "dfg", "f", "g"]
splice
let arr = [1,2,3,4,5,6];
console.log(arr.splice(2,3),arr);
// [3, 4, 5] [1, 2, 6]
toSource
//只有 Gecko 核心的浏览器（比如 Firefox）支持该方法，也就是说 IE、Safari、Chrome、Opera 等浏览器均不支持该方法。
function employee(name,job,born){
this.name = name;
this.job = job;
this.born = born;
}
let bill = new employee('Bill Gates','Engineer',1985);
console.log(bill.toSource());
//({name:"Bill Gates", job:"Engineer", born:1985})
toString
let arr = [2,3,4,5,6];
console.log(arr.toString(),arr.toString('-'));
// 2,3,4,5,6 2,3,4,5,6
toLocaleString
let arr = [2,3,4,5,6];
console.log(arr.toLocaleString());
// 2,3,4,5,6
unshift
let arr1 = [1,2,3,4,5];
let arr2 = [1,2,3,4,5];
console.log(arr1.unshift(),arr1,arr2.unshift('3'),arr2)
//5 [1, 2, 3, 4, 5] 6 ["3", 1, 2, 3, 4, 5]
valueof
let arr = [1,2,3,4,5];
console.log(arr.valueof(),arr);
//Uncaught TypeError: arr.valueof is not a function