表名和字段
–1.学生表
Student(s_id,s_name,s_birth,s_sex) –学生编号,学生姓名, 出生年月,学生性别
–2.课程表
Course(c_id,c_name,t_id) – –课程编号, 课程名称, 教师编号
–3.教师表
Teacher(t_id,t_name) –教师编号,教师姓名
–4.成绩表
Score(s_id,c_id,s_score) –学生编号,课程编号,分数
测试数据
--建表
--学生表
CREATE TABLE `Student`(
`s_id` VARCHAR(20),
`s_name` VARCHAR(20) NOT NULL DEFAULT '',
`s_birth` VARCHAR(20) NOT NULL DEFAULT '',
`s_sex` VARCHAR(10) NOT NULL DEFAULT '',
PRIMARY KEY(`s_id`)
);
--课程表
CREATE TABLE `Course`(
`c_id` VARCHAR(20),
`c_name` VARCHAR(20) NOT NULL DEFAULT '',
`t_id` VARCHAR(20) NOT NULL,
PRIMARY KEY(`c_id`)
);
--教师表
CREATE TABLE `Teacher`(
`t_id` VARCHAR(20),
`t_name` VARCHAR(20) NOT NULL DEFAULT '',
PRIMARY KEY(`t_id`)
);
--成绩表
CREATE TABLE `Score`(
`s_id` VARCHAR(20),
`c_id` VARCHAR(20),
`s_score` INT(3),
PRIMARY KEY(`s_id`,`c_id`)
);
--插入学生表测试数据
insert into Student values('01' , '赵雷' , '1990-01-01' , '男');
insert into Student values('02' , '钱电' , '1990-12-21' , '男');
insert into Student values('03' , '孙风' , '1990-05-20' , '男');
insert into Student values('04' , '李云' , '1990-08-06' , '男');
insert into Student values('05' , '周梅' , '1991-12-01' , '女');
insert into Student values('06' , '吴兰' , '1992-03-01' , '女');
insert into Student values('07' , '郑竹' , '1989-07-01' , '女');
insert into Student values('08' , '王菊' , '1990-01-20' , '女');
--课程表测试数据
insert into Course values('01' , '语文' , '02');
insert into Course values('02' , '数学' , '01');
insert into Course values('03' , '英语' , '03');
--教师表测试数据
insert into Teacher values('01' , '张三');
insert into Teacher values('02' , '李四');
insert into Teacher values('03' , '王五');
--成绩表测试数据
insert into Score values('01' , '01' , 80);
insert into Score values('01' , '02' , 90);
insert into Score values('01' , '03' , 99);
insert into Score values('02' , '01' , 70);
insert into Score values('02' , '02' , 60);
insert into Score values('02' , '03' , 80);
insert into Score values('03' , '01' , 80);
insert into Score values('03' , '02' , 80);
insert into Score values('03' , '03' , 80);
insert into Score values('04' , '01' , 50);
insert into Score values('04' , '02' , 30);
insert into Score values('04' , '03' , 20);
insert into Score values('05' , '01' , 76);
insert into Score values('05' , '02' , 87);
insert into Score values('06' , '01' , 31);
insert into Score values('06' , '03' , 34);
insert into Score values('07' , '02' , 89);
insert into Score values('07' , '03' , 98);
SELECT * from course; -- 2.课程表 Course(c_id,c_name,t_id) – –课程编号, 课程名称, 教师编号
SELECT * from score; -- 4.成绩表Score(s_id,c_id,s_score) –学生编号,课程编号,分数
SELECT * from student;-- –1.学生表 Student(s_id,s_name,s_birth,s_sex) –学生编号,学生姓名, 出生年月,学生性别
SELECT * from teacher; -- 教师表 Teacher(t_id,t_name) –教师编号,教师姓名
select 查询条件 from 表名 where 表1,2之间相同的联系 group by(分组)...having (对没有的加一起的列名提出的条件)order by (排序)
-- 1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数
select e.score,s.* from score e ,student s
where
select s.*,e.s_score,a.s_score from student s ,score e,score a
where e.s_id = s.s_id and a.s_id=s.s_id and e.c_id='01' and a.c_id='02' and a.s_score -- 2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数 select s.*,e.s_score,a.s_score from student s ,score e,score a where e.s_id = s.s_id and a.s_id=s.s_id and e.c_id='01' and a.c_id='02' and a.s_score>e.s_score -- 3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩 SELECT s.s_id,s.s_name,avg(e.s_score) FROM student s,score e WHERE e.s_id=s.s_id HAVING AVG(e. s_score)>=60 -- 4、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩 SELECT s.s_id,s.s_name,COUNT(c_id),SUM(e.s_score) FROM student s ,score e where s.s_id=e.s_id group by s.s_id,s.s_name -- 5、查询"李"姓老师的数量 SELECT * from course; -- 2.课程表 Course(c_id,c_name,t_id) – –课程编号, 课程名称, 教师编号 SELECT * from score; -- 4.成绩表Score(s_id,c_id,s_score) –学生编号,课程编号,分数 SELECT * from student;-- –1.学生表 Student(s_id,s_name,s_birth,s_sex) –学生编号,学生姓名, 出生年月,学生性别 SELECT * from teacher; -- 教师表 Teacher(t_id,t_name) –教师编号,教师姓名 select count(t_name) from teacher where t_name like '李%' -- 6、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息 select s.* from student s, score e, score a WHERE s.s_id=e.s_id and s.s_id=a.s_id and e.s_id='01' and a.s_id= '02' -- 7、检索"01"课程分数小于60,按分数降序排列的学生信息 select s.*,e.s_score from student s,score e where s.s_id=e.s_id and e.c_id='01' and e.s_score<60 ORDER BY e.s_score DESC -- 8、查询不同老师所教不同课程平均分从高到低显示 select t.t_name,AVG( e.s_score),c.c_name from teacher t,score e ,course c where c.c_id=e.c_id and c.t_id=t.t_id GROUP BY t.t_name ORDER BY avg(e.s_score) DESC -- 9、查询每门课程被选修的学生数 SELECT e.c_id,COUNT( *) from score e group by e.c_id -- 10、查询男生、女生人数 select s_sex,COUNT(*) from student group by s_sex -- 11、查询名字中含有"风"字的学生信息 SELECT * from course; -- 2.课程表 Course(c_id,c_name,t_id) – –课程编号, 课程名称, 教师编号 SELECT * from score; -- 4.成绩表Score(s_id,c_id,s_score) –学生编号,课程编号,分数 SELECT * from student;-- –1.学生表 Student(s_id,s_name,s_birth,s_sex) –学生编号,学生姓名, 出生年月,学生性别 SELECT * from teacher; -- 教师表 Teacher(t_id,t_name) –教师编号,教师姓名 SELECT * from student where s_name like '风' -- 12、查询同名同性学生名单,并统计同名人数 SELECT s_name,COUNT( *) from student GROUP by s_name HAVING COUNT(*)>1 -- 13、查询1990年出生的学生名单 SELECT * from student where s_birth=1990 -- 14、查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列 select AVG(e.s_score),c.c_name from score e, course c WHERE e.c_id=c.c_id GROUP BY c.c_name ORDER BY AVG( e.s_score) DESC , e.c_ID ASC -- 15、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩 select s.s_id,s.s_name,AVG(e.s_score) FROM student s,score e where s.s_id=e.s_id GROUP BY e.s_id HAVING AVG( e.s_score)>85 -- 16、查询不及格的课程 select c.c_name,s.s_name,e.s_score from student s,course c, score e where c.c_id=e.c_id and s.s_id=e.s_id and e.s_score<60 -- 17、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名; select s.s_id,s.s_name from student s, score e where e.s_score>80 and e.s_id='01' GROUP BY s.s_id -- 18、求每门课程的学生人数 SELECT * from course; -- 2.课程表 Course(c_id,c_name,t_id) – –课程编号, 课程名称, 教师编号 SELECT * from score; -- 4.成绩表Score(s_id,c_id,s_score) –学生编号,课程编号,分数 SELECT * from student;-- –1.学生表 Student(s_id,s_name,s_birth,s_sex) –学生编号,学生姓名, 出生年月,学生性别 SELECT * from teacher; -- 教师表 Teacher(t_id,t_name) –教师编号,教师姓名 select c_id,count(*) as "学生人数" from score GROUP BY C_Id -- 19、统计每门课程的学生选修人数(超过5人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列 select C_Id,count(*) as "学生人数" from score GROUP BY "学生人数",c_id ORDER BY "学生人数" DESC ,s_score ASC -- 20、检索至少选修两门课程的学生学号 select s_id from score GROUP BY s_score HAVING COUNT( *)>1