UIMenuController 实现长按显示自定义菜单功能

这段时间在集成使用融云聊天功能的时候，想自定义消息cell的长按的菜单，在网上查了查，这是根据 UIMenuController 实现的。具体代码如下，我是使用一个btn实现的
首先创建一个btn，并给btn添加一个长按的事件.

 UILongPressGestureRecognizer *recognizer = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(longPress:)];
 [btn addGestureRecognizer:recognizer];
 

然后实现长按方法

注意，这个控件必须要实现几个方法

1、

 [btn becomeFirstResponder];
 

2、

 
 
 
  
(BOOL)canBecomeFirstResponder{
 return YES;
 }
 

3、让该view处于可交互状态

具体代码如下

 
 
 
  
 
(void)longPress:(UILongPressGestureRecognizer *)recognizer{
 if (recognizer.state == UIGestureRecognizerStateBegan) {
 [btn becomeFirstResponder];
 UIMenuItem *flag = [[UIMenuItem alloc] initWithTitle:@"Flag"action:@selector(flag:)];
 UIMenuItem *approve = [[UIMenuItem alloc] initWithTitle:@"Approve"action:@selector(approve:)];
 UIMenuItem *deny = [[UIMenuItem alloc] initWithTitle:@"Deny"action:@selector(deny:)];
 UIMenuController *menu = [UIMenuController sharedMenuController];
 
  [menu setMenuItems:[NSArray arrayWithObjects:flag, approve, deny, nil]];
  [menu setTargetRect:btn.frame inView:btn.superview];
  [menu setMenuVisible:YES animated:YES];
 
}
 }
 

下面再写出各个菜单点击的实现方法即可，非常简单。

 
 
 
  
(void)flag:(id)sender {
 NSLog(@"Cell was flagged");
 }
 
  
(void)approve:(id)sender {
 NSLog(@"Cell was approved");
 }
 
  
(void)deny:(id)sender {
 NSLog(@"Cell was denied");
 }