1.编写一个简单程序,要求数组长度为5,静态赋值10,20,30,40,50,在控制台输出该数组的值。
package come.itheima01; import java.util.Scanner; public class Sz { public static void main(String[] args) { int[] arr = new int[] { 10, 20, 30, 40, 50 }; for (int i = 0; i < arr.length; i++) { System.out.print(arr[i] + " "); } } }
2.编写一个简单程序,要求数组长度为5,动态赋值10,20,30,40,50,在控制台输出该数组的值。
package come.itheima01; import java.util.Scanner; public class Sz { public static void main(String[] args) { int[] a = new int[6]; for (int i = 1; i < a.length; i++) { a[i]+=a[i-1]+10; System.out.print(a[i] + " "); } } }
3.编写一个简单程序,定义整型数组,里面的元素是{23,45,22,33,56},求数组元素的和、平均值
package come.itheima01;
import java.util.Scanner;
public class Sz {
public static void main(String[] args) {
int[] a = new int[]{23,45,22,33,56};
int sum=0,pj=0;
for (int i = 0; i < a.length; i++) {
sum+=a[i];
}
pj=sum/5;
System.out.println(sum + " " + pj);
}
}
4.在一个有8个整数(18,25,7,36,13,2,89,63)的数组中找出其中最大的数及其下标。
package come.itheima01; import java.util.Scanner; public class Sz { public static void main(String[] args) { int[] a = new int[] { 18, 25, 7, 36, 13, 2, 89, 63 }; int max = a[0]; for (int i = 0; i < a.length; i++) { if (max < a[i]) { max = a[i]; } } System.out.println("最大值是:" + max); int count = 0; for (int i = 0; i < a.length; i++) { if (a[i] == max) { System.out.println("下标值是:" + count); } count++; } } }
5、将一个数组中的元素逆序存放(知识点:数组遍历。数组元素访问)
package come.itheima01; public class Sz { public static void main(String[] args) { int[] grade = {87,88,89,98,78}; int m; for(int i = 0; i < 2; i++){ m = grade[i]; grade[i] = grade[5-i-1]; grade[5-i-1] = m; } for(int j =0; j < 5; j++){ System.out.println(grade[j]); } } }