PAT (Advanced Level) Practice 1060 Are They Equal

                                       1060 Are They Equal

If a machine can save only 3 significant digits, the float numbers 12300 and 12358.9 are considered equal since they are both saved as 0.123×10​5​​ with simple chopping. Now given the number of significant digits on a machine and two float numbers, you are supposed to tell if they are treated equal in that machine.

Input Specification:

Each input file contains one test case which gives three numbers N, A and B, where N (<100) is the number of significant digits, and A and B are the two float numbers to be compared. Each float number is non-negative, no greater than 10​100​​, and that its total digit number is less than 100.

Output Specification:

For each test case, print in a line YES if the two numbers are treated equal, and then the number in the standard form 0.d[1]...d[N]*10^k (d[1]>0 unless the number is 0); or NO if they are not treated equal, and then the two numbers in their standard form. All the terms must be separated by a space, with no extra space at the end of a line.

Note: Simple chopping is assumed without rounding.

Sample Input 1:

3 12300 12358.9

Sample Output 1:

YES 0.123*10^5

Sample Input 2:

3 120 128

Sample Output 2:

NO 0.120*10^3 0.128*10^3

 AC代码：

#include
#include
using namespace std;
int n;
string deal(string s,int &e){
	int k =0;
	while(s.length()>0&&s[0] == '0'){
		s.erase(s.begin());
	}
	if(s[0]=='.'){
		s.erase(s.begin());
		while(s.length()>0&&s[0]=='0'){
			s.erase(s.begin());
			e--;
		}
	}else{
		while(k> n>>s1>>s2;
	int e1=0,e2=0;
	s3=deal(s1,e1);
	s4=deal(s2,e2);
	if(s3==s4&&e1==e2){
		cout<<"YES 0."<

结果如下：