判断一个 9x9 的数独是否有效。只需要根据以下规则,验证已经填入的数字是否有效即可。
1-9
在每一行只能出现一次。1-9
在每一列只能出现一次。1-9
在每一个以粗实线分隔的 3x3
宫内只能出现一次。上图是一个部分填充的有效的数独。
数独部分空格内已填入了数字,空白格用 '.'
表示。
示例 1:
输入:
[
["5","3",".",".","7",".",".",".","."],
["6",".",".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6",".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".",".","6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
输出: true
示例 2:
输入:
[
["8","3",".",".","7",".",".",".","."],
["6",".",".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6",".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".",".","6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
输出: false
解释: 除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。
但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。
说明:
1-9
和字符 '.'
。9x9
形式的。一个数独是否有效,必须满足题目中的三个条件,那么依次判断是否满足这三个条件即可。
我的大方向是,把每一行(每一列、或每一块)的所有数字都加入一个临时数组,然后转换成set集合,判断这个数组长度与集合大小是否相等,若相等,说明无重复数字,若不等,说明有重复数字,就返回false。
所有条件都满足,最后才返回true
/**
* @param {character[][]} board
* @return {boolean}
*/
var isValidSudoku = function(board) {
// 检查每一行
for (let arr of board) {
let row = []
for (let c of arr) {
if (c !== '.') row.push(c);
}
let set = new Set(row)
if (set.size !== row.length) return false;
}
// 检查每一列
for (let i = 0; i < 9; i++) {
let col = []
board.map( arr => {
if (arr[i] !== '.') col.push(arr[i])
})
let set = new Set(col)
if (set.size !== col.length) return false;
}
// 检查每个小方块
for (let x = 0; x < 9; x += 3) {
for (let y = 0; y < 9; y += 3) {
let box = []
for (let a = x; a < 3 + x; a ++) {
for (let b = y; b < 3 + y; b ++) {
if (board[a][b] !== '.') box.push(board[a][b])
}
}
let set = new Set(box)
if (set.size !== box.length) return false
}
}
return true
};