后台返回 ajax 回调函数(json数据格式)

2019独角兽企业重金招聘Python工程师标准>>>

    //后台方法
    Model model = new Model;
    model.put("msg",true);    
    PrintWriter w;
    w = response.getWriter();
    response.setContentType("text/json; charset=utf-8");
    String res  = JsonUtil.toJson(model);
    w.write(res);
    w.close();

    //前台调用 ajax直接.属性就可以了
    $.ajax({
          type: "POST",
          url: "${ctx}/mbr/actives/add?type="+type,
          data: datas,
          success: function(msg){
             if(msg.msg==true){
                 $.messager.info("保存成功");
                 window.close();
                 refreshParent();
              }else{
                   $.messager.error("保存失败");
              }
                                    
            }
     });

转载于:https://my.oschina.net/u/1998885/blog/423271