Codeforces 916C-Jamie and Interesting Graph

Jamie and Interesting Graph
time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output

Jamie has recently found undirected weighted graphs with the following properties very interesting:

  • The graph is connected and contains exactly n vertices and m edges.
  • All edge weights are integers and are in range [1, 109] inclusive.
  • The length of shortest path from 1 to n is a prime number.
  • The sum of edges' weights in the minimum spanning tree (MST) of the graph is a prime number.
  • The graph contains no loops or multi-edges.

If you are not familiar with some terms from the statement you can find definitions of them in notes section.

Help Jamie construct any graph with given number of vertices and edges that is interesting!

Input

First line of input contains 2 integers nm  — the required number of vertices and edges.

Output

In the first line output 2 integers spmstw (1 ≤ sp, mstw ≤ 1014) — the length of the shortest path and the sum of edges' weights in the minimum spanning tree.

In the next m lines output the edges of the graph. In each line output 3 integers uvw (1 ≤ u, v ≤ n, 1 ≤ w ≤ 109) describing the edge connecting u and v and having weight w.

Examples
input
4 4
output
7 7
1 2 3
2 3 2
3 4 2
2 4 4
input
5 4
output
7 13
1 2 2
1 3 4
1 4 3
4 5 4
Note

The graph of sample 1:Codeforces 916C-Jamie and Interesting Graph_第1张图片Shortest path sequence: {1, 2, 3, 4}. MST edges are marked with an asterisk (*).

Definition of terms used in the problem statement:

shortest path in an undirected graph is a sequence of vertices (v1, v2, ... , vk) such that vi is adjacent to vi + 1 1 ≤ i < k and the sum of weight  is minimized where w(i, j) is the edge weight between i and j. (https://en.wikipedia.org/wiki/Shortest_path_problem)

prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself. (https://en.wikipedia.org/wiki/Prime_number)

minimum spanning tree (MST) is a subset of the edges of a connected, edge-weighted undirected graph that connects all the vertices together, without any cycles and with the minimum possible total edge weight. (https://en.wikipedia.org/wiki/Minimum_spanning_tree)

https://en.wikipedia.org/wiki/Multiple_edges


题意:构造出一张n个点m条边的有向图,并且不存在环和重边,1到n的最短路为质数,最小生成树也为质数

解题思路:先将1连向其他所有点,除了1~n-1这条边,其他边的权值都为2,算出大于等于2*(n-1)的最小质数,然后确定1~n-1这条边的权值,若边数不够,则再加上其他边权为1000000000的边即可


#include    
#include    
#include    
#include    
#include    
#include    
#include    
#include    
#include    
#include    
#include    
#include 

using namespace std;

#define LL long long   
const int INF = 0x3f3f3f3f;

int vis[1000009];
int n, m, prime[1000009], cnt, tot;

struct Edge
{
	int u, v, w;
}x[100009];

void init()
{
	memset(vis, 0, sizeof vis);
	vis[0] = vis[1] = 1;
	cnt = 0;
	for (int i = 2; i < 1000000; i++)
	{
		if (vis[i]) continue;
		prime[cnt++] = i;
		for (int j = 2 * i; j < 1000000; j += i) vis[j] = 1;
	}
}

int main()
{
	init();
	while (~scanf("%d%d", &n, &m))
	{
		if (n == 2)
		{
			printf("2 2\n");
			printf("1 2 2\n");
			continue;
		}
		int tmp = 2 * (n - 1);
		tot = 0;
		int k = lower_bound(prime, prime + cnt, tmp) - prime;
		printf("2 %d\n", prime[k]);
		x[tot].u = 1, x[tot].v = n, x[tot].w = 2;
		tot++;
		for (int i = 2; i < n - 1; i++)
		{
			x[tot].u = 1, x[tot].v = i, x[tot].w = 2;
			tot++;
		}
		x[tot].u = 1, x[tot].v = n - 1, x[tot].w = prime[k] - 2 * (n - 2);
		tot++;
		for (int i = 2; i <= n; i++)
		{
			if (tot >= m) break;
			for (int j = i + 1; j <= n; j++)
			{
				x[tot].u = i, x[tot].v = j, x[tot].w = 100000000;
				tot++;
				if (tot >= m) break;
			}
		}
		for (int i = 0; i < tot; i++) printf("%d %d %d\n", x[i].u, x[i].v, x[i].w);
	}
	return 0;
}

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