PAT甲级推荐做题顺序按照19年9月4日通过率排序

试题编号	通过率
1113	0.63%
1120	0.62%
1008	0.59%
1064	0.58%
1099	0.57%
1094	0.55%
1092	0.54%
1011	0.53%
1083	0.51%
1102	0.51%
1027	0.50%
1054	0.50%
1127	0.49%
1051	0.47%
1056	0.47%
1125	0.47%
1020	0.46%
1130	0.46%
1134	0.46%
1140	0.46%
1155	0.46%
1006	0.45%
1115	0.45%
1030	0.44%
1053	0.44%
1086	0.44%
1138	0.44%
1036	0.43%
1066	0.43%
1114	0.43%
1142	0.43%
1146	0.43%
1041	0.42%
1058	0.42%
1106	0.42%
1050	0.41%
1084	0.41%
1090	0.41%
1124	0.41%
1147	0.41%
1042	0.40%
1116	0.40%
1037	0.39%
1063	0.39%
1079	0.39%
1123	0.39%
1128	0.39%
1076	0.38%
1107	0.38%
1148	0.38%
1149	0.38%
1031	0.37%
1045	0.37%
1049	0.37%
1004	0.36%
1119	0.36%
1121	0.36%
1019	0.35%
1043	0.35%
1062	0.35%
1071	0.35%
1087	0.35%
1109	0.35%
1154	0.35%
1005	0.34%
1028	0.34%
1070	0.34%
1093	0.34%
1129	0.34%
1150	0.34%
1059	0.33%
1073	0.33%
1098	0.33%
1118	0.33%
1013	0.32%
1038	0.32%
1097	0.32%
1104	0.32%
1105	0.32%
1122	0.32%
1133	0.32%
1022	0.31%
1023	0.31%
1039	0.31%
1040	0.31%
1069	0.31%
1091	0.31%
1136	0.31%
1034	0.30%
1035	0.30%
1044	0.30%
1048	0.30%
1088	0.30%
1089	0.30%
1100	0.30%
1145	0.30%
1046	0.29%
1081	0.29%
1103	0.29%
1132	0.29%
1003	0.28%
1009	0.28%
1024	0.28%
1033	0.28%
1068	0.28%
1074	0.28%
1144	0.28%
1025	0.27%
1032	0.27%
1065	0.27%
1067	0.27%
1111	0.27%
1015	0.26%
1021	0.26%
1047	0.26%
1057	0.26%
1082	0.26%
1085	0.26%
1108	0.26%
1135	0.26%
1137	0.26%
1001	0.25%
1012	0.25%
1018	0.25%
1095	0.25%
1110	0.25%
1112	0.25%
1141	0.25%
1151	0.25%
1017	0.24%
1072	0.24%
1078	0.24%
1096	0.24%
1152	0.24%
1080	0.23%
1101	0.23%
1117	0.23%
1126	0.23%
1131	0.23%
1143	0.23%
1060	0.22%
1061	0.22%
1002	0.21%
1014	0.21%
1016	0.21%
1052	0.21%
1055	0.21%
1077	0.21%
1075	0.20%
1153	0.20%
1007	0.19%
1139	0.18%
1026	0.16%
1010	0.11%
1029	0.10%

	string s;
	ifstream cin("PATLOG.txt");
	map > M;
	while(getline(cin,s)){
		double d;
		int i;
		sscanf(s.substr(s.find_last_of('\t')).c_str(),"%lf",&d);
		sscanf(s.c_str(),"%d",&i);
		M[d].push_back(i);
	} 
	for(auto it=M.rbegin();it!=M.rend();++it){
		vector &v=it->second;
		sort(v.begin(),v.end());
		double d= it->first;
		for(int i=0;i